Question

我希望我的imageView能够在用户点击时打开url/link。我搜索了一些例子但主要是它不适合片段。任何人都可以帮助我吗？

HomeFragment.java

public class HomeFragment extends Fragment{

{


public HomeFragment(){}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {

    View rootView = inflater.inflate(R.layout.fragment_main, container, false);

    ImageView img = (ImageView)rootView.findViewById(R.id.imageViewTwitter);
    img.setOnClickListener(new View.OnClickListener(){
        public void onClick(View v){
            Intent intent = new Intent();
            intent.setAction(Intent.ACTION_VIEW);
            intent.addCategory(Intent.CATEGORY_BROWSABLE);
            intent.setData(Uri.parse("http://twitter.com"));
            startActivity(intent);
        }
    });

    ImageView img2 = (ImageView)rootView.findViewById(R.id.imageViewIG);
    img.setOnClickListener(new View.OnClickListener(){
        public void onClick(View v){
            Intent intent = new Intent();
            intent.setAction(Intent.ACTION_VIEW);
            intent.addCategory(Intent.CATEGORY_BROWSABLE);
            intent.setData(Uri.parse("https://www.instagram.com/?hl=en"));
            startActivity(intent);
        }
    });

    ImageView img3 = (ImageView)rootView.findViewById(R.id.imageViewFB);
    img.setOnClickListener(new View.OnClickListener(){
        public void onClick(View v){
            Intent intent = new Intent();
            intent.setAction(Intent.ACTION_VIEW);
            intent.addCategory(Intent.CATEGORY_BROWSABLE);
            intent.setData(Uri.parse("https://www.facebook.com"));
            startActivity(intent);
        }
    });
    return rootView;


}}

fragmnet_main.xml

    <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@drawable/back"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context="com.example.eventstory.MainActivity$PlaceholderFragment" >

<ImageView
    android:id="@+id/imageView2"
    android:layout_width="fill_parent"
    android:layout_height="match_parent"
    android:scaleType="fitXY"
    android:src="@drawable/homepage" />

<ImageView
    android:id="@+id/imageViewIG"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignBottom="@+id/imageView2"
    android:layout_centerHorizontal="true"
    android:layout_marginBottom="20dp"
    android:src="@drawable/instagramlogo"

    />

<ImageView
    android:id="@+id/imageViewTwitter"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentRight="true"
    android:layout_alignTop="@+id/imageViewIG"
    android:src="@drawable/twitter" />

<ImageView
    android:id="@+id/imageViewFB"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignLeft="@+id/imageView2"
    android:layout_alignTop="@+id/imageViewIG"
    android:src="@drawable/logofacebook" />

唯一的ImageView工作是imageViewTwitter，但它链接到facebook.com而不是twiiter。另一个ImageView无效

Answer 1

必须足够：

...
...
      ImageView img = (ImageView)rootView.findViewById(R.id.imageViewTwitter);
        img.setOnClickListener(new View.OnClickListener(){
            public void onClick(View v){
              Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://twitter.com"));
    getActivity().startActivity(intent);    
            }
        });

        ImageView img2 = (ImageView)rootView.findViewById(R.id.imageViewIG);
        img2.setOnClickListener(new View.OnClickListener(){
            public void onClick(View v){
              Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("https://www.instagram.com/?hl=en"));
    getActivity().startActivity(intent);
            }
        });

        ImageView img3 = (ImageView)rootView.findViewById(R.id.imageViewFB);
        img3.setOnClickListener(new View.OnClickListener(){
            public void onClick(View v){
              Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.gmail.com"));
    getActivity().startActivity(intent);
                intent.setData(Uri.parse("https://www.facebook.com"));
                startActivity(intent);
            }
        });
...
...

您的问题是您要将onClickListeners分配给同一个ImageView（img）！

  ImageView img2 = (ImageView)rootView.findViewById(R.id.imageViewIG);
  img.setOnClickListener...

  ImageView img3 = (ImageView)rootView.findViewById(R.id.imageViewIG);
  img.setOnClickListener...

Answer 2

以下代码可用于在浏览器中打开 link / url 。

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.gmail.com"));
getActivity().startActivity(intent);

背后的原因startActivity()不在片段中工作，因为它是为Activity而不是片段写的。为了能够调用此函数，您需要获取此应用程序的上下文

示例：

getApplictionContext().startActivity("call your relevant intent");

在Android片段中将ImageView设置为URL

2 个答案: