Question

我有一个手机号码字段，我想查看是否有任何数字重复9次，包括零和if 任何仅由两个不同数字组成的电话号码或手机号码。

有没有正则表达式或其他什么可以做到这一点？

在葡萄牙，电话号码以2 ########开头，移动电话以91/92/93/96开头，两者都有9位数字。

Answer 1

此正则表达式仅匹配9个以2或91,92,93,96

开头的后续数字

(?:2\d|9[1236]) =字符串的开头

[0-9]{7} = 2 +任何数字 OR 9跟随1,2,3或6

$ = 7个数字

C:\poppler-0.24.5\include\src =字符串结尾

Answer 2

试试这个正则表达式：

^(?:(?:(2)([013-9])|(9)([1236]))(?!(?:\1|\2){7})(?!(?:\3|\4){7})\d{7}|(?=2{2,7}([^2])(?!(?:2|\5)+\b))22\d{7})\b

Regex live here.

解释

^                              # from start
(?:                            # look at (?:...) as subsets
  (?:                          # 
    (2)([013-9])|(9)([1236])   # store possible digits in groups \1 \2 \3 \4
  )                            #
  (?!(?:\1|\2){7})             # in front cannot repeat only \1 \2
  (?!(?:\3|\4){7})             # neither only \3 \4
  \d{7}                        # plus seven digits to complete nine
|                              # or
  (?=                          # to avoid number repetitions:
    2{2,7}([^2])               # in front should be possible to match
                               # the number 2 from 2 to seven times 
                               # and another digit stored in \5
    (?!(?:2|\5)+\b)            # but not only them,
                               # so, should match another digit 
                                   # (not two or the \5) till the boundary
  )                            #
  22\d{7}                      # then, it refers to 22 and 7 digits = nine
)\b                            # confirm it don't overflows nine digits

希望它有所帮助。

验证移动电话和电话号码 - 外部系统

2 个答案: