Question

我正在尝试使用JavaScript和PHP制作注册表单，但我遇到了问题。 JavaScript代码不会将数组发送到register_submit.php。我已尝试在互联网上查看一些示例以及StackOverflow上的其他帖子，但没有一个答案似乎解决了我自己的问题。

用户进入registration.php页面，填写表单并点击调用checkForms（）方法的提交按钮。 setValues（）方法将注册表单中的值设置为单个变量。我检查了检索到的变量是否正确（它们是）。

编辑：问题不在于有两个$ password变量。意外测试错误。

JavaScript代码：

function checkForms() {
    setValues();
    callPHP();
}

function callPHP() {


    alert(registration.emailR);
        // call ajax
        $.ajax({
            type: "POST",
            url: 'register_submit.php',
            data:{name:registration.usernameR, email:registration.emailR, password:registration.password1R, forename:registration.forenameR, surname:registration.surnameR, country:registration.countryR, dob:registration.dobR},
            success:function(msg) {
                alert("Register Complete");    
            }    
        });

        // Go to homepage
        window.location.href = "index.php";

}

PHP代码：

<?php
    $username = $_POST['username'];
    $email = $_POST['email'];
    $password = $_POST['password'];
    $forename = $_POST['forename'];
    $surname = $_POST['surname'];
    $country = $_POST['country'];
    $dob = $_POST['dob'];

    $host = "host";
    $user = "user";
    $password = "password";
    $database = "database";

$con = new mysqli($host, $user, $password, $database);

if(!$con)
    die('Connection failed'.mysql_error());
else echo "Connection successful  ";
mysqli_select_db($con, $database);

        $query = "INSERT INTO user (userID, username, dob, email, password, isAuthor, isAdmin, country, surname, firstname) VALUES ('user001', '$username', '$dob', '$email', '$password', '0', '0', '$country', '$surname', '$forename')";
        echo $query;
        mysqli_query($con, $query);
        echo "Registration Complete!!";
?>

Answer 1

Ajax是异步的，这意味着它在后台运行，直到作业完成，你在ajax完成此行之前离开页面：

window.location.href = "index.php";

将其置于成功方法内：

success:function(msg)
{
    alert ("Register Complete");
    window.location.href = "index.php"; 
}

数据未从javascript函数发送到php表单

1 个答案: