如何访问ForeignKey数据而不在Wagtail中进行额外的查询(django)

时间:2015-12-15 12:25:13

标签: python django django-models wagtail

我在app.models中有以下两个类,我使用wagtail API将数据作为json

class AuthorMeta(Page):
    author=models.OneToOneField(User)
    city = models.ForeignKey('Cities', related_name='related_author')

class Cities(Page):
    name = models.CharField(max_length=30)

因此,当我尝试/api/v1/pages/?type=dashboard.AuthorMeta&fields=title,city时,它会返回以下数据:

{
    "meta": {
        "total_count": 1
    },
    "pages": [
        {
            "id": 11,
            "meta": {
                "type": "dashboard.AuthorMeta",
                "detail_url": "http://localhost:8000/api/v1/pages/11/"
            },
            "title": "Suneet Choudhary",
            "city": {
                "id": 10,
                "meta": {
                    "type": "dashboard.Cities",
                    "detail_url": "http://localhost:8000/api/v1/pages/10/"
                }
            }
        }
    ]
}

在城市字段中,它会返回城市的idmeta。如何在此处获取响应中的城市名称,而无需进行额外查询? :/

我无法在Documentation中找到任何解决方案。我错过了什么吗?

2 个答案:

答案 0 :(得分:4)

使用Django model属性返回ForeignKey:

class AuthorMeta(Page):
    author=models.OneToOneField(User)
    city = models.ForeignKey('Cities', related_name='related_author')
    city_name = property(get_city_name)

    def get_city_name(self):
        return self.city.name

检查Term Property以更好地理解概念

答案 1 :(得分:2)

如果您在Streamfield中有外键,例如PageChooserBlock,您可以通过覆盖块的get_api_representation来自定义api响应,如示例here中所述:

class CustomPageChooserBlock(blocks.PageChooserBlock):
    """ Customize the api response. """

    def get_api_representation(self, value, context=None):
        """ Return the url path instead of the id. """
        return value.url_path