所以我一直在和Flask＆amp; Apache服务器上的Bootstrap。我已经达到了可以访问应用程序的程度。使用以下路线渲染“第一个”或“主要”模板：
来自view.py的：
@app.route('/')
def fn_home():
return render_template("main.html")
不幸的是，每次尝试从main.html路由到另一个网页/功能都会失败。我正在使用导航栏列表href中的“url_for”函数，尝试让烧瓶向Apache提供xls-upload.html网页。
来自main.html的：
<div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1">
<ul class="nav navbar-nav">
<li><a href="{{ url_for('upload') }}">Upload Spreadsheets </a></li>
：
@app.route('/upload')
def upload():
return render_template("xls-upload.html")
看起来函数正在使用，因为URL更改为http://myapp/upload，但html页面不会被函数呈现/返回 - 而是收到404“Not Found”。我似乎无法从函数返回任何内容，甚至return "Hello World"。
似乎“看起来像”Apache正在尝试解析http://myapp/upload路径，而不是向Flask应用程序打开一个套接字，然后通过该套接字发送html。我不确定这是否是一个FCGI问题，如果我错过了相对/绝对路径问题，误解了Flask的一般工作原理，或者是所有的一些组合等等。
我是Flask的新手，所以我希望有人可以帮助我，因为我真的觉得自己走到了尽头。
提前致谢！
我的烧瓶应用程序结构如下：
以下是我的适用文件：
1）/etc/httpd/conf.d/myapp：
<VirtualHost *:80>
ServerAdmin webmaster@localhost
DocumentRoot /var/www/cgi-bin/myapp/static/
ServerName myapp
Alias /static/ /var/www/cgi-bin/myapp/static/
ScriptAlias / /var/www/cgi-bin/myapp/start.fcgi
<Directory "var/www/cgi-bin/myapp">
AllowOverride None
Order allow,deny
Allow from all
AuthType Basic
AuthUserFile /etc/httpd/.htpasswd
AuthName 'Enter Password'
Require valid-user
</Directory>
</VirtualHost>
2）/var/www/cgi-bin/myapp/start.fcgi：
#!/usr/bin/python
# IMPORTS:
from flup.server.fcgi import WSGIServer
from view import app
if __name__ == '__main__':
WSGIServer(app).run()
3）/var/www/cgi-bin/myapp/view.py:
#!/usr/bin/python
# IMPORTS:
import os
from flask import Flask, render_template, url_for, request, session, redirect
from werkzeug import secure_filename
# STATIC VARIABLES
UPLOAD_FOLDER = 'var/www/cgi-bin/myapp/xls-dir'
ALLOWED_EXTENSIONS = set(['xls'])
## flask:
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
# FUNCTIONS
def fn_allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route('/')
def fn_home():
return render_template("main.html")
@app.route('/upload')
def upload():
return render_template("xls-upload.html")
#return "HI there"
if __name__ == '__main__':
app.run(debug=True, host='0.0.0.0')
4）/var/www/cgi-bin/myapp/templates/main.html：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- The above 3 meta tags *must* come first in the head; any other head content must come *after* these tags -->
<title>ALG Tools HOME</title>
<!-- Bootstrap -->
<link href="{{ url_for('static', filename = 'css/bootstrap.min.css') }}" rel="stylesheet">
</head>
<nav class="navbar navbar-default">
<div class="container-fluid">
<!-- Brand and toggle get grouped for better mobile display -->
<div class="navbar-header">
<button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1" aria-expanded="false">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="/">ALG Tool - HOME</a>
</div>
<!-- Collect the nav links, forms, and other content for toggling -->
<div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1">
<ul class="nav navbar-nav">
<li><a href="{{ url_for('upload') }}">Upload Spreadsheets </a></li>
<li><a href="/xls-download.html">Download Spreadsheets</a></li>
<li><a href="/cfg-generate.html">Generate Configs</a></li>
</ul>
</div>
</div>
</nav>
<body>
<h2>ALG stuff</h2>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="{{ url_for('static', filename = 'js/bootstrap.min.js') }}"></script>
</body>
</html>
5）/var/www/cgi-bin/myapp/templates/xls-upload.html：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- The above 3 meta tags *must* come first in the head; any other head content must come *after* these tags -->
<title>ALG XLS Upload</title>
<!-- Bootstrap -->
<link href="{{ url_for('static', filename = 'css/bootstrap.min.css') }}" rel="stylesheet">
</head>
<nav class="navbar navbar-default">
<div class="container-fluid">
<!-- Brand and toggle get grouped for better mobile display -->
<div class="navbar-header">
<button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1" aria-expanded="false">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="/">ALG Tool - HOME</a>
</div>
<!-- Collect the nav links, forms, and other content for toggling -->
<div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1">
<ul class="nav navbar-nav">
<li><a href="/xls-upload.html">Upload Spreadsheets </a></li>
<li><a href="/xls-download.html">Download Spreadsheets</a></li>
<li><a href="/cfg-generate.html">Generate Configs</a></li>
</ul>
</div>
</div>
</nav>
<body>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="{{ url_for('static', filename = 'js/bootstrap.min.js') }}"></script>
</body>
</html>
答案 0 :(得分：0)
FCGI并不是一种推荐的Python Web应用程序服务方式。您应该研究运行WSGI的众多方法之一。
但是，假设您出于某种原因需要执行此操作，则会出现轻微的配置问题，这是导致问题的原因;你需要在ScriptAlias路径上使用尾部斜杠。
ScriptAlias / /var/www/cgi-bin/myapp/start.fcgi/
有了这个，Apache将传递start.fcgi脚本的完整路径，而不是替换它。
请注意，即使使用FCGI，也不应将您的应用代码放在cgi-bin中。它并不需要在那里，因为它不像CGI应用程序那样由Web服务器运行。实际上，您的代码根本不应该在/ var / www下。