在Android中流式传输实时图像

时间:2015-12-15 10:21:44

标签: android image stream android-videoview

我是这样的流源链接: http://210.245.17.188:8090/stream911 这是一个实时图像源列表,而不是视频源(您可以在浏览器中打开上面的链接以查看它的外观)。现在我想将这些图像流式传输到设备,如流媒体视频。我已经使用VideoView来传输此链接,但它没有用。我该如何解决这个问题?

1 个答案:

答案 0 :(得分:0)

您可以使用VideoView执行此操作,我的示例代码如下:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent" >

    <VideoView
        android:id="@+id/VideoView"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:layout_centerHorizontal="true"
        android:layout_centerVertical="true" />

</RelativeLayout>

java class

public class VideoViewActivity extends Activity {

    // Declare variables
    ProgressDialog pDialog;
    VideoView videoview;

    // Insert your Video URL
    String VideoURL = "http://www.androidbegin.com/tutorial/AndroidCommercial.3gp";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        // Get the layout from video_main.xml
        setContentView(R.layout.videoview_main);
        // Find your VideoView in your video_main.xml layout
        videoview = (VideoView) findViewById(R.id.VideoView);
        // Execute StreamVideo AsyncTask

        // Create a progressbar
        pDialog = new ProgressDialog(VideoViewActivity.this);
        // Set progressbar title
        pDialog.setTitle("Android Video Streaming Tutorial");
        // Set progressbar message
        pDialog.setMessage("Buffering...");
        pDialog.setIndeterminate(false);
        pDialog.setCancelable(false);
        // Show progressbar
        pDialog.show();

        try {
            // Start the MediaController
            MediaController mediacontroller = new MediaController(
                    VideoViewActivity.this);
            mediacontroller.setAnchorView(videoview);
            // Get the URL from String VideoURL
            Uri video = Uri.parse(VideoURL);
            videoview.setMediaController(mediacontroller);
            videoview.setVideoURI(video);

        } catch (Exception e) {
            Log.e("Error", e.getMessage());
            e.printStackTrace();
        }

        videoview.requestFocus();
        videoview.setOnPreparedListener(new OnPreparedListener() {
            // Close the progress bar and play the video
            public void onPrepared(MediaPlayer mp) {
                pDialog.dismiss();
                videoview.start();
            }
        });

    }

}