Question

我是Django的新手，并尝试根据URL中的不同值设置分页。

在views.py

中

class PageListView(ListView):
    model = FbPage
    paginate_by = 50

    all_pages = False

    def dispatch(self, *args, **kwargs):
        self.request.session['all_pages'] = self.all_pages
        return super(PageListView, self).dispatch(*args, **kwargs)

在网址中：

    url(r'^$', PageListView.as_view(), name='show_page_list'),
    url(r'^all/$', PageListView.as_view(all_pages=True), name='all_show_page_list'),

在模板中：

        <div class="pagination">

        <span class="page-links">
            {% if page_obj.has_previous %}

                    <a href="{% url 'show_page_list' %}?page={{ page_obj.previous_page_number }}">previous</a>
            {% endif %}
            <span class="page-current">
                Page {{ page_obj.number }} of {{ page_obj.paginator.num_pages }} (total {{ page_obj.paginator.count }} items).
            </span>
            {% if page_obj.has_next %}
                <a href="{% url 'show_page_list' %}?page={{ page_obj.next_page_number }}">next</a>
            {% endif %}
        </span>
    </div>

问题是，即使我在home/all页面，它也会链接回home页面分页，因为我通过了show_page_list而不是all_show_page_list

如何在模板中设置if else以便我可以正确分页，或者我应该做一些不同的事情？

Answer 1

您可以在上下文变量中定义模式名称，并将其传递到{% url %}标记：

<div>
   <div class="pagination">

    <span class="page-links">
        {% if page_obj.has_previous %}

                <a href="{% url list_url %}?page={{ page_obj.previous_page_number }}">previous</a>
        {% endif %}
        <span class="page-current">
            Page {{ page_obj.number }} of {{ page_obj.paginator.num_pages }} (total {{ page_obj.paginator.count }} items).
        </span>
        {% if page_obj.has_next %}
            <a href="{% url list_url %}?page={{ page_obj.next_page_number }}">next</a>
        {% endif %}
    </span>
</div>

在你看来：

class PageListView(ListView):
    model = FbPage
    paginate_by = 50

    all_pages = False

    def dispatch(self, *args, **kwargs):
        self.request.session['all_pages'] = self.all_pages
        return super(PageListView, self).dispatch(*args, **kwargs)

    def get_context_data(self, **kwargs):
        context = super(PageListView, self).get_context_data(**kwargs)

        context['list_url'] = 'all_show_page_list' if self.all_pages else 'show_page_list'

        return context

Django Pagination基于视图中的布尔值

1 个答案: