Question

我开始对此感到愤怒

mysql_query无法识别我的变量$d1，即使我尝试重命名

这是代码..

HTML：

<form action ="manageVessel.php" method ="POST">
  <select onchange ="this.form.submit();" class ="form-control" name ="ViewPositionCertificates">
      <option>Choose a Position </option>                                                       
      <?php
      $ViewPCertificates = mysql_query("SELECT * FROM table_cmsjob") or die("error" . mysql_error());
      while ($rwViewPCertificates = mysql_fetch_array($ViewPCertificates)) {
          ?>
          <option value =" <?php echo $rwViewPCertificates['jobName']; ?> "> <?php echo $rwViewPCertificates['jobName']; ?></option>  
      <?php } ?>

       </select>   
</form>

PHP：

   <?php if (isset($_POST['ViewPositionCertificates'])) { ?>
      <table class = "table table-bordered">
          <tr class ="bg-primary">
              <td> List of Certificates </td>
          </tr>
          <?php
          $d1 = $_POST['ViewPositionCertificates'];
          echo $_POST['ViewPositionCertificates'];
          $ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '$d1' ") or die("error" . mysql_error());

          while ($rwViewCertificatesFP = mysql_fetch_array($ViewCertificatesFP)) {

              echo "<tr>";
              echo "<td>" . $rwViewCertificatesFP['Certificate'] . "</td>";
              echo "</tr>";
          }
          ?>

      </table>




  <?php } ?>

当我使用字符串例如

时，

MYSQL WHERE子句正常工作

    mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  'MASTER' ") or die("error" . mysql_error());

但是当我使用变量将$_POST['ViewPositionCertificates']分配给变量时，MYSQL WHERE子句不会读取任何帮助吗？

Answer 1

<option value ="<?php echo $rwViewPCertificates['jobName']; ?>"> <?php echo $rwViewPCertificates['jobName']; ?></option>   // remove xtra spaces from here......

从value属性

中删除空格

Answer 2

试试这样..

$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".mysql_real_escape_string(trim($d1))."' ") or die("error" . mysql_error());

或

$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".addslashes(trim($d1))."' ") or die("error" . mysql_error());

Answer 3

<?php if (isset($_POST['ViewPositionCertificates'])) { ?>
    <table class = "table table-bordered">
        <tr class ="bg-primary">
            <td> List of Certificates </td>
        </tr>
        <?php
        $d1 = $_POST['ViewPositionCertificates'];
        echo $_POST['ViewPositionCertificates'];
        $ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".$d1."' ") or die("error" . mysql_error());

        while ($rwViewCertificatesFP = mysql_fetch_array($ViewCertificatesFP)) {

            echo "<tr>";
            echo "<td>" . $rwViewCertificatesFP['Certificate'] . "</td>";
            echo "</tr>";
        }
        ?>
    </table>
<?php } ?>

选择查询语法的更改使用单引号。

Answer 4

试试这个：

mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  ".$_POST['ViewPositionCertificates'])

Answer 5

您不能在单引号内编写变量，如果您编写它，那么PHP会将其视为字符串。所以你的查询将是
log4net

如需更多帮助，请阅读PHP中的变量插值

Answer 6

尝试更改您的查询方法可能有所帮助......

$ViewCertificatesFP = mysql_query("SELECT * FROM table_cmsjobassigning WHERE jobName =  '".$d1."' ") or die("error" . mysql_error());

php mysql where子句不读取变量

6 个答案: