我有以下DQL查询
SELECT
ps.id,
MAX(ps.dueDate) as due_date,
u.firstName as first_name,
u.lastName as last_name,
u.email,
IDENTITY(ps.loanApplication) as loan_application_id,
DATE_DIFF(MAX(ps.dueDate), CURRENT_DATE()) as diff
FROM
Loan\Entity\PaymentSchedule ps
LEFT JOIN
ps.paymentType pt
LEFT JOIN
ps.loanApplication la
LEFT JOIN
la.status s
LEFT JOIN
la.user u
WHERE
pt.slug != :paymentSlug AND s.keyIdentifier = :status AND diff = 14
GROUP BY
ps.loanApplication
转换为以下SQL查询
SELECT
p0_.id AS id_0,
MAX(p0_.due_date) AS sclr_1,
u1_.first_name AS first_name_2,
u1_.last_name AS last_name_3,
u1_.email AS email_4,
p0_.loan_application_id AS sclr_5,
DATEDIFF(MAX(p0_.due_date), CURRENT_DATE) AS sclr_6
FROM
payment_schedule p0_
LEFT JOIN
payment_type p2_ ON p0_.payment_type_id = p2_.id
LEFT JOIN
loan_application l3_ ON p0_.loan_application_id = l3_.id
LEFT JOIN
loan_application_status l4_ ON l3_.loan_application_status_id = l4_.id
LEFT JOIN
user u1_ ON l3_.user_id = u1_.id
WHERE
p2_.slug <> ? AND l4_.key_identifier = ? AND sclr_6 = 14
GROUP BY
p0_.loan_application_id
这给了我以下错误
======================================================================
PDOException
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'sclr_6' in 'where clause'
----------------------------------------------------------------------
当我替换WHERE条件
时WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status AND diff = 14
使用
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status
它完美运行并显示正确的记录,我也尝试了WHERE条件
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status AND DATE_DIFF(MAX(ps.dueDate), CURRENT_DATE()) = :days_diff
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status HAVING (DATE_DIFF(MAX(ps.dueDate), CURRENT_DATE())) = :days_diff
以上WHERE不起作用,我在这里缺少什么?
感谢。
答案 0 :(得分:1)
如果要在WHERE子句中使用别名,则需要sub-select
。
select *
from
(SELECT
p0_.id AS id_0,
MAX(p0_.due_date) AS sclr_1,
u1_.first_name AS first_name_2,
u1_.last_name AS last_name_3,
u1_.email AS email_4,
p0_.loan_application_id AS sclr_5,
DATEDIFF(MAX(p0_.due_date), CURRENT_DATE) AS sclr_6
FROM
payment_schedule p0_
LEFT JOIN
payment_type p2_ ON p0_.payment_type_id = p2_.id
LEFT JOIN
loan_application l3_ ON p0_.loan_application_id = l3_.id
LEFT JOIN
loan_application_status l4_ ON l3_.loan_application_status_id = l4_.id
LEFT JOIN
user u1_ ON l3_.user_id = u1_.id
) A
WHERE
slug <> ? AND key_identifier = ? AND sclr_6 = 14
这是逻辑处理查询的方式
FROM clause
WHERE clause
SELECT clause
GROUP BY clause
HAVING clause
ORDER BY clause
由于Where
出现在Select
之前,您无法在alias name
子句中使用Where
答案 1 :(得分:0)
您不能在WHERE
子句中使用别名(在最终结果字段中);但是,至少对于MySQL,您可以使用HAVING
子句而不需要GROUP BY
。
答案 2 :(得分:0)
您使用的表达式是聚合的结果。替换添加having
子句,使查询看起来像;
SELECT . . .
WHERE p2_.slug <> ? AND l4_.key_identifier = ?
GROUP BY p0_.loan_application_id
HAVING sclr_6 = 14
请注意date_diff()
不是MySQL中的函数。你打算datediff()
。