Question

我是Swift的新手，我正在努力建立一个简单的程序，告诉用户他们出生在中国日历的年份根据他们的年龄。

    var string1 = "You are year of the"
    let age:Int? = Int(ageField.text!)

    if age <= 12 {
        let remainder = age!
    } else {
        let remainder = age! % 12
    }

    if remainder == 0 {
        string1 += " sheep."
    }; if remainder == 1 {
        string1 += " horse."
    }; if remainder == 2 {
        string1 += " snake."
    }; if remainder == 3 { // And so on and so forth...

我在每条“if”行上收到一条错误消息，指出二元运算符'=='不能应用于'_'和'Int'类型的操作数。我有什么想法可以解决这个问题？

Answer 1

变量/常量SELECT Sub.name, Sub.N_Certificates, MAX(Sub.N_Certificates) OVER () - Sub.Certificates AS Difference FROM ($_query_$) AS SUB应该在remainder构造之外声明，你也可以删除字符＆＃34 ;;＆＃34;在你的代码中。斯威夫特不需要＆＃34;;＆＃34;在指令结束时，如objective-c

Answer 2

作为Alessandro答案的摘要和优化代码看起来像

的评论

var string1 = "You are year of the"
if let age = Int(ageField.text!) {

    let remainder = age % 12

    if remainder == 0 {
        string1 += " sheep."
    } else if remainder == 1 {
        string1 += " horse."
    } else if remainder == 2 {
        string1 += " snake."
    } // And so on and so forth...

} else {
    print("please enter a number")
}

或使用switch语句

有点“更快”

var string1 = "You are year of the "
if let age = Int(ageField.text!) {

    switch age % 12 {

    case 0: string1 += "sheep."
    case 1: string1 += "horse."
    case 2: string1 += "snake."
        // And so on and so forth...
    }

} else {
    print("please enter a number")
}

PS：实际上羊是山羊; - ）

Swift错误：二进制运算符==无法应用于类型'_'和'Int'

2 个答案: