Question

我想知道这里是否有人可以帮我改一下，所以我只能works来works id prod_instruments_id + number + works_instruments都在SELECT `works`.`id`, `composers`.`first_name` FROM `works` JOIN `composers` ON `works`.`composers_id` = `composers`.`id` JOIN `works_instruments` ON `works`.`id` = `works_instruments`.`works_id` WHERE (true) AND `composers`.`full_name` LIKE '%karl friedrich abel%' AND `works_instruments`.`prod_dd_instruments_id` = 15 AND `works_instruments`.`number` >= 1 AND `works_instruments`.`prod_dd_instruments_id` = 5 AND `works_instruments`.`number` >= 1 AND `works`.`work_no` <> '001' AND `works`.`short_title` NOT LIKE '%*Works' ORDER BY `composers`.`last_name`, `composers`.`first_name`, `works`.`full_title` LIMIT 0,50？

中找到

这就是我所拥有的：

SELECT 
    `works`.`id`, 
    `composers`.`first_name` 
FROM `works` 
    JOIN `composers` ON `works`.`composers_id` = `composers`.`id` 
    JOIN `works_instruments` ON `works`.`id` = `works_instruments`.`works_id` 
WHERE 
    (true) 
    AND `composers`.`full_name` LIKE '%karl friedrich abel%' 
    AND `works_instruments`.`prod_dd_instruments_id` = 15 
    AND `works_instruments`.`number` >= 1 
    AND `works`.`work_no` <> '001' AND `works`.`short_title` NOT LIKE '%*Works' 
ORDER BY 
    `composers`.`last_name`, 
    `composers`.`first_name`, 
    `works`.`full_title` 
LIMIT 0,50

现在这不会返回任何结果。不过这样做：

SELECT 
    `works`.`id`, 
    `composers`.`first_name` 
FROM `works` 
    JOIN `composers` ON `works`.`composers_id` = `composers`.`id` 
    JOIN `works_instruments` ON `works`.`id` = `works_instruments`.`works_id` 
WHERE 
    (true) 
    AND `composers`.`full_name` LIKE '%karl friedrich abel%'  
    AND `works_instruments`.`prod_dd_instruments_id` = 5 
    AND `works_instruments`.`number` >= 1 
    AND `works`.`work_no` <> '001' AND `works`.`short_title` NOT LIKE '%*Works' 
ORDER BY 
    `composers`.`last_name`, 
    `composers`.`first_name`, 
    `works`.`full_title` 
LIMIT 0,50

这样做：

SELECT 
    `works`.`id`, 
    `composers`.`first_name` 
FROM `works` 
    JOIN `composers` ON `works`.`composers_id` = `composers`.`id` 
    LEFT JOIN `works_instruments` ON `works`.`id` = `works_instruments`.`works_id` 
WHERE 
    (true) 
    AND `composers`.`full_name` LIKE '%karl friedrich abel%' 
    AND `works_instruments`.`prod_dd_instruments_id` = 15 
    AND `works_instruments`.`number` >= 1 
    AND `works_instruments`.`prod_dd_instruments_id` = 5 
    AND `works_instruments`.`number` >= 1 
    AND `works`.`work_no` <> '001' AND `works`.`short_title` NOT LIKE '%*Works' 
ORDER BY 
    `composers`.`last_name`, 
    `composers`.`first_name`, 
    `works`.`full_title` 
LIMIT 0,50

你能帮忙吗？

我也试过LEFT和RIGHT加入，但仍然是一个空结果（我只是在这里粘贴左边）：

works_instruments

works_instruments没有uniqe ID是一个问题吗？在此处查看getline的屏幕截图： Screenshot

Answer 1

没有数字值，其中字段可以同时= 15和= 5。相反，您可以执行＆＃34; IN（15,5）＆＃34 ;,按works.id分组，并计算不同的prod_dd_instruments_id值以查看是否有两个;或者使用不同的标准集在两个相同的表中进行两个单独的连接。

修改：根据您在下面提供的其他信息，此类内容可能会更有帮助。

SELECT works.*, composers.*
, SUM(IF(wi.prod_dd_instruments_id=15, wi.number, 0)) AS count15
, SUM(IF(wi.prod_dd_instruments_id=5, wi.number, 0)) AS count5
FROM works 
INNER JOIN `composers` ON `works`.`composers_id` = `composers`.`id` 
LEFT JOIN `works_instruments` AS wi ON `works`.`id` = wi.`works_id`
WHERE [the other criteria you had]
GROUP BY works.id
HAVING count15 > 1 AND count5 > 1
;

请注意，此查询仅适用于＆＃34; 5＆amp; 15＆＃34 ;;虽然（从您的＆＃34; (true)＆＃34判断;我猜你正在部分地在代码中构建查询，所以我认为将上面的内容稍微变得不会太难代码更灵活。

Mysql JOIN：仅当连接中的多行匹配时才选择SELECT

1 个答案: