Question

我有两张桌子如下。下面提到的两个表中的Id列值都是自动递增的的组
+----+-----------+----------------+
| Id | GroupId | GroupName |
+----+-----------+----------------+
| 1 | 10 | Grp1@abc.com |
| 2 | 20 | Grp2@abc.com |
| 3 | 30 | Grp3@xyz.com |
| 4 | 40 | Grp4@def.com |
+----+-----------+----------------+

客户
+---+-----------------+------------+----------+---------------+
| Id | GroupAliasName | Domain | GroupId | CustomerName |
+---+-----------------+------------+----------+---------------+
| 1 | Grp1 | abc.com | null | Cust1 |
| 2 | Grp2 | abc.com | null | Cust2 |
| 3 | Grp3 | xyz.com | null | Cust3 |
| 4 | Grp4 | def.com | null | Cust4 |
+---+-----------------+------------+----------+---------------+

现在来自客户表格'GroupAliasName'和'Domain'，当'GroupAliasName@Domain'连接时相当于群组中的'GroupName'表

使用客户表中的连接值，我需要从组表中提取'GroupId'并在客户中填充 表格'GroupId'如下

客户
+----+----------------+------------+----------+---------------+
| Id | GroupAliasName | Domain | GroupId | CustomerName |
+----+----------------+-----------+---------+-----------------+
| 1 | Grp1 | abc.com | 10 | Cust1 |
| 2 | Grp2 | abc.com | 20 | Cust2 |
| 3 | Grp3 | xyz.com | 30 | Cust3 |
| 4 | Grp4 | def.com | 40 | Cust4 |
+----+----------------+------------+----------+---------------+

我尝试的查询如下

UPDATE Customer SET GroupId = (SELECT GroupId FROM Group G WHERE GroupName = (SELECT CONCAT(GroupAliasName, '@', Domain) AS GroupName FROM Customer WHERE Domain IS NOT NULL) AND G.GroupName = GroupName);

但我收到的错误为'Subquery returns more than 1 row' 请建议或提供您的意见。

Answer 1

尝试这样的事情

UPDATE Customer as c
INNER JOIN Group as g on (  CONCAT(c.GroupAliasName, '@', c.Domain) =  g.GroupName)
SET c.GroupId = g.GroupId;

Answer 2

试试这个：

update customer as cust
inner join `group` grp on  concat(cust.groupaliasname, '@', cust.domain) =  grp.groupname
set cust.groupId = grp.groupId;

通过使用另一个表值查询连接的列值来更新列值

2 个答案: