Question

我已经用PHP编写了登录页面的代码。当我提交登录详细信息时，即使我已编写代码以重定向到其他页面，该页面也只是被重定向到自身。请帮我确定错误的位置。

代码看起来像这样

<?php
session_start();

    $username = $password= "";
    $usernameErr = $passwordErr = "";
    $empty = false;

    if($_SERVER["REQUEST_METHOD"] == "POST")
    {
        if(empty($_POST["username"]))
        {
            $empty = true;
            $usernameErr="Username is empty. Please try again";
        }
        else 
            {
                $username = $_POST["username"];
            }
        if(empty($_POST["password"]))
        {
            $empty = true;
            $passwordErr="Password is empty. Please try again";
        }
        else 
            {
                $password = $_POST["password"];
            }
        if(!$empty)
        {
            $servername = "myxor.in.mysql";
            $dbusername = "myxor_in";
            $dbpassword = "srikanth177";
            $dbname = "myxor_in";
            // Create connection
            $conn = new mysqli($servername, $dbusername, $dbpassword, $dbname);
            // Check connection
            if ($conn->connect_error) 
            {
                die("Connection failed: " . $conn->connect_error);
            } 

            $sql = "SELECT firstname,password,package FROM users WHERE username='$username'";
            $result = $conn->query($sql);

            if (($result->num_rows) > 0) 
            {
                $row = $result->fetch_assoc();


                    if($username === $row['username']) 
                    {
                        if($password === $row['password'])
                        {
                            echo "came here";
                            $_SESSION['fname'] = $row['firstname'];
                            $_SESSION['pack'] = $row['package'];
                            $_SESSION['login_user'] = $username;
                            header("Location: http://www.myxor.in/home.php");

                        }
                        else
                        {
                            $passwordErr = "Invalid Password. Please Try Again";
                        }
                    }

            } else
            {
                $usernameErr = "Invalid Username. Please Try Again";
            }
        }
    }
?>

<head>
  <style>
  td{
       color:red;
      }
  </style>
  <title>Login Page</title>
</head>

<body>

<h2 align=center style="color:blue">Login Form</h2>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post">
<table align=center bgcolor=grey >
<tr>
    <td><label>UserName :</label>
    <td><input id="name" name="username" placeholder="username" type="text">
    <td><?php echo $usernameErr?></td>
<tr>
    <td><label>Password :</label>
    <td><input id="password" name="password" placeholder="**********" type="password">
    <td><?php echo $passwordErr?></td>
<tr>
    <td colspan=2 align=center><input name="submit" type="submit" value=" Login ">
</table>

</form>
</body>
</html>

Answer 1

这就是问题所在：

<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post">

您正在使用$ _SERVER [＆＃34; PHP_SELF＆＃34;]将表单发送到同一个网址（除非您希望将表单发送到您的情况下的其他网址，否则这实际上是有效的）。将操作更改为要将表单发送到的URL以进行验证。 E.g。

<form action="validate_form.php" method="post">
.....

Answer 2

试试这个：

<?php
session_start();

include("validations.php");

$username = "";
$password= "";
$usernameErr = $passwordErr = "";
$empty = false;

if(isset($_POST['submit'])
{
    if(empty($_POST["username"]))
    {
        $empty = true;
        $usernameErr="Username is empty. Please try again";
    }
    else 
        {
            $username = $_POST["username"];
        }
    if(empty($_POST["password"]))
    {
        $empty = true;
        $passwordErr="Password is empty. Please try again";
    }
    else 
        {
            $password = $_POST["password"];
        }
    if(!$empty)
    {
        $servername = "myxor.in.mysql";
        $dbusername = "myxor_in";
        $dbpassword = "srikanth177";
        $dbname = "myxor_in";
        // Create connection
        $conn = new mysqli($servername, $dbusername, $dbpassword, $dbname);
        // Check connection
        if ($conn->connect_error) 
        {
            die("Connection failed: " . $conn->connect_error);
        } 

        $sql = "SELECT firstname,password,package FROM users WHERE         username='$username'";
        $result = $conn->query($sql);

        if (($result->num_rows) > 0) 
        {
            $row = $result->fetch_assoc();


                if($username === $row['username']) 
                {
                    if($password === $row['password'])
                    {
                        echo "came here";
                        $_SESSION['fname'] = $row['firstname'];
                        $_SESSION['pack'] = $row['package'];
                        $_SESSION['login_user'] = $username;
                        header('Location: http://www.myxor.in/home.php');
                        exit;
                    }
                    else
                    {
                        $passwordErr = "Invalid Password. Please Try Again";
                    }
                }

        } else
        {
            $usernameErr = "Invalid Username. Please Try Again";
        }
    }
}
?>

<head>
  <style>
  td{
   color:red;
  }
  </style>
  <title>Login Page</title>
</head>

<body>

    <h2 align=center style="color:blue">Login Form</h2>
    <form action="this_page.php"  method="post">
<table align=center bgcolor=grey >
<tr>
<td><label>UserName :</label>
<td><input id="name" name="username" placeholder="username" type="text">
<td><?php echo $usernameErr?></td>
<tr>
<td><label>Password :</label>
<td><input id="password" name="password" placeholder="********** type="password">
<td><?php echo $passwordErr?></td>
<tr>
 <td colspan=2 align=center><input name="submit" type="submit" value=" Login     ">
</table>

</form>
</body>
</html>

你有：$username = $password = ""; 我将其更正为$username = ""; $password="";

我改变了一些HTML 我在html中更改的是表单操作，而不仅仅是<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post">

我将其更改为：<form action="yourpagevalidation.php" method="post">

我在header

之后添加了退出

我将您的if($_REQUEST[]内容更改为if(isset($_POST['submit']))

Answer 3

或者你可以这样做：

<form action="<?php echo $_SERVER["PHP_SELF"];?>" method="post">

Answer 4

谢谢你们的帮助。我自己发现了这个错误。错误是我试图从行中访问“用户名”而不在查询中选择用户名。所以它出了故障。我通过在选择列表中添加用户名列来纠正它。再次感谢你。

PHP登录表单无法正常运行

4 个答案: