在这样的场景中,当我们有一个对象时,
Object1 = function(param1){
this.attribute1=function(param1){
console.log("executing");
//random business logic could be anything
var newRelationship;
switch (param1){
case "epic": newRelationship= new Epic([this.startPoint, this.endPoint]);
break;
case "lame": newRelationship = "lamest";
break;
}
console.log(newRelationship);
return newRelationship;
}
}
对象属性实际上并没有在构造函数调用时设置,例如
var moveCircle = new Object1("epic)
,意味着如果任何其他属性依赖于这一个对象属性,我们将遇到一些问题。
一种解决方案是实现一个setter并在构造对象后立即调用它来设置我们的属性,但这意味着不需要在对象构造函数签名中包含该参数。
Object1 = function(){
this.attribute1=""
this.setAttribute1 = function(param1){
console.log("executing");
//random business logic could be anything
var newRelationship;
switch (param1){
case "epic": newRelationship= new Epic([this.startPoint, this.endPoint]);
break;
case "lame": newRelationship = "lamest";
break;
}
console.log(newRelationship);
this.attribute1 = newRelationship;
}
}
然而由于某种原因(不能想到一个)我们只是想或者需要将参数作为构造函数的一部分,在创建新的实例时确保它被设置的最佳方法是什么?对象类型?我提出的解决方案是简单地将属性匿名函数自我声明,但是在这种情况下,无论何时在运行时访问该属性,“业务逻辑”正在重新运行,这是愚蠢的。
Object1 = function(param1){
this.attribute1=function(param1){
console.log("executing");
//random business logic could be anything
var newRelationship;
switch (param1){
case "epic": newRelationship= new Epic([this.startPoint, this.endPoint]);
break;
case "lame": newRelationship = "lamest";
break;
}
console.log(newRelationship);
return newRelationship;
}
}()
有人可以告诉我解决这个问题的最佳方法是什么,通常的做法是什么以及使用setter并省略对象签名中的参数的现实场景是不可行的
答案 0 :(得分:1)
首先声明函数,然后在构造函数中使用它。
Object1 = function(param1){
function foo(param1){
console.log("I am called only once!");
//random business logic could be anything
var newRelationship;
switch (param1){
case "epic": newRelationship = "epic";
break;
case "lame": newRelationship = "lamest";
break;
}
console.log(newRelationship);
return newRelationship;
}
this.attribute1 = foo(param1);
}
var obj = new Object1('epic');
obj.attribute1;
obj.attribute1;
obj.attribute1;
obj.attribute1;
obj.attribute1;
obj.attribute1;
console.log(obj.attribute1);