Question

完整代码为here，以下是我的代码，在调用library(data.table) setDT(df)[2:3, names := 'elisa'] df # names #1: george #2: elisa #3: elisa #4: tony时，它始终会引发new PagerAdapter(fragmentManager)

Container.groovy

Could not find matching constructor for: ro.vst.Container$PagerAdapter(ro.vst.Container, android.app.FragmentManagerImpl)

错误：

void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState)
    setContentView(R.layout.container)
    ViewPager pager = (ViewPager) findViewById(R.id.pager)

    PagerAdapter pagerAdapter = new PagerAdapter(fragmentManager)
    pager.setAdapter(pagerAdapter)
}

class PagerAdapter extends FragmentPagerAdapter {
    PagerAdapter(FragmentManager fm) {
        super(fm)
    }

    @Override
    Fragment getItem(int position) {
        return new Slider();
    }

    @Override
    int getCount() {
        return 2
    }
}

更新即使我将代码更改为Caused by: groovy.lang.GroovyRuntimeException: Could not find matching constructor for: ro.vst.Container$PagerAdapter(ro.vst.Container, android.app.FragmentManagerImpl) at groovy.lang.MetaClassImpl.invokeConstructor(MetaClassImpl.java:1723) at groovy.lang.MetaClassImpl.invokeConstructor(MetaClassImpl.java:1526) at org.codehaus.groovy.runtime.callsite.MetaClassConstructorSite.callConstructor(MetaClassConstructorSite.java:46) at org.codehaus.groovy.runtime.callsite.CallSiteArray.defaultCallConstructor(CallSiteArray.java:57) at org.codehaus.groovy.runtime.callsite.AbstractCallSite.callConstructor(AbstractCallSite.java:232) at org.codehaus.groovy.runtime.callsite.AbstractCallSite.callConstructor(AbstractCallSite.java:252) at ro.vst.Container.onCreate(Container.groovy:19) at android.app.Activity.performCreate(Activity.java:5933)，错误仍然存在

Answer 1

您的fragmentManager不匹配。片段管理器应该是相同的，android.app ....或android.support.v4 .....

所以在你的代码中请尝试

pager.setAdapter(new MyAdapter(getFragmentManager()));

getFragmentManager（）位于android.support.v4.app.Fragment

下

并在你的适配器

public MyAdapter(FragmentManager fm) {
    super(fm);

}

这里'FragmentManager fm'在android.support.v4.app.FragmentManager下;

新的内部类总是提出“找不到构造函数”

1 个答案: