我编写了一个shell脚本,当我在本地测试时,它可以很好地工作。
bin/cake myshell method
但是当我把它指定为crob时,它不能正常工作。相反,我看到了默认的蛋糕输出:
Welcome to CakePHP v3.1.4 Console
---------------------------------------------------------------
App : src
Path: /home/fantastagram/public_html/src/
PHP : 5.6.16
---------------------------------------------------------------
Current Paths:
* app: src
* root: /home/fantastagram/public_html
* core: /home/fantastagram/public_html/vendor/cakephp/cakephp
Available Shells:
[Migrations] migrations
[CORE] i18n, orm_cache, plugin, routes, server
[app] console, instagram
To run an app or core command, type `cake shell_name [args]`
To run a plugin command, type `cake Plugin.shell_name [args]`
To get help on a specific command, type `cake shell_name --help`
Content-type: text/html; charset=UTF-8
似乎忽略了脚本的两个参数。我在cPanel中使用了cron jobs工具......
我做错了什么?
答案 0 :(得分:1)
我打开调试,发现脚本实际上在我的参数之前出错了。我用Google搜索了错误,结果是:Cakephp 3 bin/cake bake - Undefined variable: argv
调整了php.ini配置,它运行得很好。