Question

我有一个小的Haskell Pipe打印出它运行了多少次：

counterPipe :: Pipe String String IO r
counterPipe = go 0
  where
    go n = do
      await >>= yield
      let n' = succ n
      liftIO $ putStrLn $ "Chunk " ++ show n'
      go n'

我希望能够在处理完最后一个块后打印出一条消息，并可能执行其他任务。我该怎么做呢？

Answer 1

我能够通过将counterPipe的输入类型更改为Maybe String并在上游管道完成后注入额外的Nothing来实现此功能：

import Pipes
import Pipes.Core (respond)
import Control.Applicative ((<*))

withEOF :: (Monad m) => Proxy a' a b' b m r -> Proxy a' a b' (Maybe b) m r
withEOF p = for p (respond . Just) <* respond Nothing

counterPipe :: Pipe (Maybe String) String IO Int
counterPipe = go 0
  where
    go n = do
        mx <- await

        case mx of
            Just x -> do
                yield x
                let n' = succ n
                liftIO $ putStrLn $ "Chunk " ++ show n'
                go n'
            Nothing -> do
                return n

finishCounter :: Int -> Pipe a b IO ()
finishCounter n = liftIO $ putStrLn $ unwords ["Finished after", show n, "chunks"]

示例驱动程序：

import qualified Pipes.Prelude as P
main = runEffect $ withEOF P.stdinLn >-> (counterPipe >>= finishCounter) >-> P.stdoutLn

我认为这种模式应该可以抽象为

whileJust :: (Monad m) => Proxy a' a b' b m r -> Proxy a' (Maybe a) b' b m (Maybe r)

所以你可以写

withEOF P.stdinLn >-> (whileJust counterPipe >>= maybe (return ()) finishCounter) >-> P.stdoutLn

无需更改原始counterPipe定义; 但我之前从未使用Pipes（上面的解决方案只是通过查看类型和玩类型多米诺来计算出来）因此我没有设法写whileJust（签名可能过于通用，我无法弄清楚。）

如何检测Haskell管道中的最后一个块？

1 个答案: