Question

我正在制作生活游戏，我希望有一个窗口（在我的代码中称为Grid），它使用第二个网格（称为SecGrid）信息刷新

import numpy as np
import pylab as pl
from random import randint


i = 0
o = 0


#Chose Grid size
m = int(input("Enter the width and length of the Grid: ",))
n = m
print("Your Grid will be",m,"x",n)
Grid = np.zeros((m+2,n+2))
SecGrid = np.zeros((m+2,n+2))

#Random /Grid filling in
while(i <= n/3*m):
    i = i+1
    Grid[randint(1,m), randint(1,n)] = 1
img = pl.imshow(Grid, cmap = 'PuRd', interpolation = 'none')

#Main algo
while (o < 2):
    print(o)
    v = input("continue: ")
    o = o + 1
    for i in range(1,m):
        for j in range(1,n):
            #Nbr of entities
            nbr = 0
            for k in range(-1,1):
                for l in range(-1,1):
                    nbr = nbr + Grid[i+k,j+l]
            #cells that are alive
            if Grid[i,j] == 1:
                if nbr > 1 and nbr < 4:
                    SecGrid[i,j] = 1
                else:
                    SecGrid[i,j] = 0
                #cells that are dead
            else:
                    if nbr == 3:
                        SecGrid[i,j] = 1
                    else: 
                        SecGrid[i,j] = 0

如何使用新信息刷新网格？

我试过这个

Grid = SecGrid
pl.draw(img)
img.set_data(Grid)

但我是python的新手，所以我不知道._。请帮助meh：3

Answer 1

pylab绘制方法不带任何参数。看看从命令行运行python的绘图文档。

For example:
$ python
>>> import pylab as pl
>>> help(pl.draw)

关于您的问题“如何使用新信息刷新网格？”，当您在“随机/网格填写”注释中更新网格中的值时，我将假设您询问如何更新该数据在你的img对象中。如果是这样，请参阅以下内容：

# Note: entered in your code line by line into python at command line then
>>> help(img.set_data)

Help on method set_data in module matplotlib.image:

set_data(self, A) method of matplotlib.image.AxesImage instance
    Set the image array

    ACCEPTS: numpy/PIL Image A

Python：TypeError：draw（）接受0位置参数，但给出了1

1 个答案: