Question

如何在mainloop函数中获取Accessme的值？

def example():
    test=True
    while test:
       print("some stuff")
       if test2==True:
          Accessme = 400                   # Need to access this
          print("some stuff")
             if test3==True:
                print("some stuff")
                mainloop(x,y)
       elif test2==False:
          print("some stuff")

def mainloop(x,y):
   cheese = 1
   noise = []
   for something in somecodehere:
       print("some stuff") 
   output = some more code here
   print("some stuff",Accessme )          #Calling from here

这是我得到的错误：

> NameError: name 'Accessme' is not defined

Answer 1

你的示例代码很乱，所以我简化了以便你理解这个概念：

def example():
    test=True
    while test:
       Accessme = 400 #Assign the variable
       break
    return Accessme #This will return the variable. Accessme is local to the function example and nowhere else. 

def mainloop(x=0,y=0):
    cheese = 1
    noise = []
    print("some stuff",example() ) #You can grab the output from example by calling the function example, not Accessme.

mainloop()

我建议你阅读Scope。您的问题是Accessme不在mainloop的范围内。

Answer 2

如果您想要访问Accessme是全局的（即，在任何特定函数之外），那么您需要告诉每个函数这种情况：

global Accessme

使用全局变量通常是糟糕的。如果您想从函数中获取信息，最好返回该信息，就像将信息输入函数最好通过参数完成。

从另一个函数访问函数中的变量？蟒蛇

2 个答案: