我正在尝试执行以下操作:
var i = -(abs(-3))
或
var i = -abs(-3)
或
var i = -abs(3)
或
var i = -(abs(3))
但是我得到一个错误,说使用减号是模棱两可的。为什么呢?
答案 0 :(得分:5)
对我来说,这看起来像编译器错误,文字3
的类型
应该是Int
。但编译器抱怨
error: ambiguous use of operator '-'
var i = -(abs(-3))
^
Swift.-:2:20: note: found this candidate
prefix public func -(x: Float) -> Float
^
Swift.-:2:20: note: found this candidate
prefix public func -(x: Double) -> Double
^
Swift.-:2:20: note: found this candidate
prefix public func -(x: Float80) -> Float80
^
CoreGraphics.-:2:20: note: found this candidate
prefix public func -(x: CGFloat) -> CGFloat
您可以使用明确的Int
作为参数来解决此问题:
var i = -(abs(-Int(3)))
或在结果上使用类型注释:
var i : Int = -(abs(-3))
正如@vacawama所注意到的,还有更多可能的解决方案。
将任何子表达式转换为Int
会使编译器满意:
var i1 = -(abs(-(3 as Int)))
var i2 = -(abs((-3) as Int))
var i3 = -(abs(-3) as Int)
var i4 = -(abs(-3)) as Int
答案 1 :(得分:2)
我同意@MartinR这看起来像编译器错误。那么问题出在哪里?
我的实验指出一元减去是罪魁祸首。请注意,即使:
var i = -(3)
失败了:
error: ambiguous use of operator '-' var i = -(3) ^ Swift.-:2:20: note: found this candidate prefix public func -(x: Float) -> Float ^ Swift.-:2:20: note: found this candidate prefix public func -(x: Double) -> Double ^ Swift.-:2:20: note: found this candidate prefix public func -(x: Float80) -> Float80 ^ CoreGraphics.-:2:20: note: found this candidate prefix public func -(x: CoreGraphics.CGFloat) -> CoreGraphics.CGFloat**
这个简单的表达方式:
var i = -(3 + 2)
失败了:
error: ambiguous use of operator '+' var i = -(3 + 2) ^ Swift.+:2:13: note: found this candidate public func +(lhs: Float, rhs: Float) -> Float ^ Swift.+:2:13: note: found this candidate public func +(lhs: Double, rhs: Double) -> Double ^ Swift.+:2:13: note: found this candidate public func +(lhs: Float80, rhs: Float80) -> Float80 ^ CoreGraphics.+:2:13: note: found this candidate public func +(lhs: CoreGraphics.CGFloat, rhs: CoreGraphics.CGFloat) -> CoreGraphics.CGFloat
每次都有四种类型 Float , Double , Float80 和 CoreGraphics.CGFloat 斯威夫特难以决定。为什么只有这四个? 为什么那里没有Int?特别是因为Swift默认将整数文字视为Int
。