在架构x86_64中找不到JsonCpp符号

Question

我是C ++的新手，正在使用JsonCpp将C ++对象解析为Json，反之亦然。但是，以下代码不断给出错误如下：

$("#CityId").on('click',function(e){
    e.preventDefault();
    var htmlText = "<ul class=ulList>";
    var mainDiv = $('.divCounties');
    var items = "";
    for (var i = 0; i < arrCity.length; i++) {
        htmlText += "<li class=ilceCaption>" + arrCity[i].text; // +"</li>";
        htmlText += "<ul>";
        $.getJSON("../Adds/GetCounties", {cityId: arrCity[i].value }, function(data){
            $.each(data, function(i, state) {
                items += state.Text;
                //htmlText += "<li>" + state.Text + "</li>";
            }); 
            console.log(items); // ==> is getting correct value in this line**    
        });
        htmlText += "</ul>";
        htmlText += "</li>";
        console.log(items); // ==> is getting string empty value in this line**
    }
    htmlText += "</ul>";
    console.log(htmlText);
    mainDiv.html(htmlText);
});

以下是代码Account.cpp：

Undefined symbols for architecture x86_64:
  "Json::Value::Value(Json::ValueType)", referenced from:
      Account::toJson() in Account.o
  "Json::Value::Value(int)", referenced from:
      Account::toJson() in Account.o
  "Json::Value::~Value()", referenced from:
      Account::toJson() in Account.o
ld: symbol(s) not found for architecture x86_64