我无法使用指向嵌套结构的指针,并在我的类的成员函数中的那些结构中使用这些变量。
我声明了这些变量。如果它们在结构的嵌套方面被宣布为正确的,请告诉我。
const int MAX_ACCOUNT_COUNTRY = 36;
const int MAX_ACCOUNT_CITY = 50;
const int MAX_ACCOUNT_NAME = 10;
const int MAX_NUMBER = 16;
const int MAX_ACCOUNT_ADDRESS = 25;
const int MAX_ACCOUNT_EMAIL = 50;
const int MAX_OFFICE_HOURS = 20;
const int businessID = 0;
const int residentalID = 1;
typedef char accountCountry[MAX_ACCOUNT_COUNTRY + 1];
typedef char accountCity[MAX_ACCOUNT_CITY + 1];
typedef char accountName[MAX_ACCOUNT_NAME + 1];
typedef char phoneNumberFormat[MAX_NUMBER + 1];
typedef char accountAddress[MAX_ACCOUNT_ADDRESS + 1];
typedef char accountEmail[MAX_ACCOUNT_EMAIL + 1];
typedef char officeHours[MAX_OFFICE_HOURS + 1];
typedef phoneBook * phonebookPtr;
public:
Phonebook(const int numPages);
~Phonebook();
void addAccount(const int);
void removeAccount(const int);
void editAccount(const int);
void viewPhonebook();
private:
struct phoneBook{
struct businessAccountEntry
{
const int businessID;
accountCountry businessCountry;
accountCity businessCity;
accountName businessName;
accountName accountHolder;
accountAddress businessAddress;
accountAddress mailingAddress;
phoneNumberFormat phoneNumber;
phoneNumberFormat faxNumber;
accountEmail businessEmail;
officeHours businessOfficeHours;
};
struct residentialAccountEntry
{
const int residentialID;
accountName residentName;
accountAddress mailingAddress;
phoneNumberFormat phoneNumber;
};
};
phonebookPtr thePhonebook;
int counterID = 0;
Phonebook();
Phonebook(Phonebook &);
};
如何在我的班级中为我的成员函数访问结构businessAccountEntry
内的变量?
答案 0 :(得分:0)
给他们一个像
这样的名字struct phoneBook{
struct businessAccountEntry
{
const int businessID;
accountCountry businessCountry;
accountCity businessCity;
accountName businessName;
accountName accountHolder;
accountAddress businessAddress;
accountAddress mailingAddress;
phoneNumberFormat phoneNumber;
phoneNumberFormat faxNumber;
accountEmail businessEmail;
officeHours businessOfficeHours;
} businessAccount;
struct residentialAccountEntry
{
const int residentialID;
accountName residentName;
accountAddress mailingAddress;
phoneNumberFormat phoneNumber;
} residentialAccount;
};
并使用它:thePhonebook->residentialAccount.residentialID