Question

我正在编写SQL查询并在执行查询时收到错误。

SELECT tableA.*, 
A.tableB.Id AS Item,
B.tableB.Id AS Number
FROM tableA
    JOIN tableB AS A
        ON tableA.DefinitionId1 = tableB.DefinitionId
    JOIN tableB AS B
        ON tableA.DefinitionId2 = tableB.DefinitionId

这给了我错误：

Msg 4104, Level 16, State 1, Line 6
The multi-part identifier "tableB.DefinitionId" could not be bound.
Msg 4104, Level 16, State 1, Line 8
The multi-part identifier "tableB.DefinitionId" could not be bound.
Msg 207, Level 16, State 1, Line 2
Invalid column name tableB'.
Msg 207, Level 16, State 1, Line 3
Invalid column name 'tableB'.

我正在尝试从tableA中获取2列，并将它们与tableB中的1列匹配。为什么它会给我这个错误，即使我正在为这两个选项创建别名，以及我有什么选择来解决这个问题？

Answer 1

将您的查询更改为：

SELECT 
    A.*, 
    B1.Id AS Item,
    B2.Id AS Number
FROM tableA A
    JOIN tableB AS B1
        ON A.DefinitionId1 = B1.DefinitionId
    JOIN tableB AS B2
        ON A.DefinitionId2 = B2.DefinitionId

如果您已为表定义了别名，请继续在整个查询中使用它（加入和SELECT部分）

多部分标识符未使用别名绑定：SQL Server

1 个答案: