Question

我如何在PHP中编写一个函数来合并具有类似商店营业时间的日子。例如，如果我们有：

Mon  : 9:00AM - 7:00PM
Tue  : 9:00AM - 10:00PM
Wed  : 9:00AM - 7:00PM
Thu  : 9:00AM - 10:00PM
Fri  : 9:00AM - 7:00PM
Sat  : 9:00AM - 10:00PM
Sun  : 9:00AM - 7:00PM

我希望代码输出为：

Mon,Wed,Fri,Sun - 9:00AM - 7:00PM
Tue,Thu,Sat - 9:00AM - 10:00PM

以下是我尝试解决的代码。

$openHours = array(
    'Mon' => '9am-7pm',
    'Tue' => '9am-10pm',
    'Wed' => '9am-7pm',
    'Thu' => '9am-10pm',
    'Fri' => '9am-7pm',
    'Sat' => '9am-10pm',
    'Sun' => '9am-7pm'
);

$summary = array();
foreach ($openHours as $day => $hours) {
    if (!array_key_exists($hours, $summary))
        $summary[$hours] = array($day);
    else
        $summary[$hours][] = $day;
}

foreach ($summary as $hours => $days) {
    echo array_shift($days) . '-' . array_pop($days) . ' ' . $hours . PHP_EOL;
}

Answer 1

这应该适合你：

首先，我们更改数组结构，并使用时间作为键，将天数作为值使用此代码：

foreach($openHours as $k => $v)
    $array[$v][] = $k;

所以我们最终得到一个像这样的数组结构：

Array
(
    [9am-7pm] => Array
        (
            [0] => Mon
            [1] => Wed
            [2] => Fri
            [3] => Sun
        )

    [9am-10pm] => Array
        (
            [0] => Tue
            [1] => Thu
            [2] => Sat
        )

)

之后我们只需要循环遍历新数组并将implode()天数循环到以逗号分隔的字符串，并在其后添加时间。

代码：

<?php

    $openHours = array(
        'Mon' => '9am-7pm',
        'Tue' => '9am-10pm',
        'Wed' => '9am-7pm',
        'Thu' => '9am-10pm',
        'Fri' => '9am-7pm',
        'Sat' => '9am-10pm',
        'Sun' => '9am-7pm'
    );


    foreach($openHours as $k => $v)
        $array[$v][] = $k;

    foreach($array as $time => $days)
        echo implode(",", $days) . " " . $time . PHP_EOL;

?>

输出：

Mon,Wed,Fri,Sun 9am-7pm
Tue,Thu,Sat 9am-10pm

Answer 2

$ closetime = [＆＃39; 7：00＆＃39; =＆gt; [＆＃39;周一＆＃39;＆＃39;周三＆＃39;＆＃39;周五＆＃39;，＆＃ 39;阳光＆＃39;]   ＆＃39; 10：00＆＃39; =＆GT; [＆＃39;星期二＆＃39;＆＃39;周四＆＃39;＆＃39;星期六＆＃39;]];

foreach（$ closetime为$ time =＆gt; $ days）{echo explode（＆＃39;，＆＃39;，$ days）。＆＃34;    - 9:00 - ＆＃34;。$ time; }

或类似的东西

基于匹配小时数的组天数

2 个答案: