我有这个代码用于通过警报管理器设置多个通知:
接收机
public class NotificationPublisher extends BroadcastReceiver {
public static String NOTIFICATION_ID = "notification-id";
public static String NOTIFICATION = "notification";
public void onReceive(Context context, Intent intent) {
NotificationManager notificationManager = (NotificationManager)context.getSystemService(Context.NOTIFICATION_SERVICE);
Notification notification = intent.getParcelableExtra(NOTIFICATION);
notificationManager.notify(intent.getIntExtra(NOTIFICATION_ID, 0), notification);
}
}
主要
private void scheduleNotification(Notification notification, int delay) {
Intent notificationIntent = new Intent(this, NotificationPublisher.class);
notificationIntent.putExtra(NotificationPublisher.NOTIFICATION_ID, (int)System.currentTimeMillis());
notificationIntent.putExtra(NotificationPublisher.NOTIFICATION, notification);
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, (int)System.currentTimeMillis(), notificationIntent, PendingIntent.FLAG_UPDATE_CURRENT);
long futureInMillis = System.currentTimeMillis() + delay;
AlarmManager alarmManager = (AlarmManager)getSystemService(Context.ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, futureInMillis, pendingIntent);
}
private Notification getNotification(String content) {
Notification.Builder builder = new Notification.Builder(this);
builder.setContentTitle("Scheduled Notification");
builder.setContentText(content);
builder.setSmallIcon(R.drawable.ic_notification_appicon);
builder.setDefaults(Notification.DEFAULT_SOUND);
builder.setDefaults(Notification.DEFAULT_VIBRATE);
builder.setAutoCancel(true);
builder.setLights(Color.BLUE, 500, 500);
return builder.getNotification();
}
在创建我把这段代码:
scheduleNotification(getNotification("3 second delay"), 3000);
scheduleNotification(getNotification("5 second delay"), 5000);
两个通知都会显示,但两者同时显示(5秒后)我的错误在哪里?
答案 0 :(得分:1)
好的,我找到了解决方案!
我改变了:
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, (int)System.currentTimeMillis(), notificationIntent, PendingIntent.FLAG_UPDATE_CURRENT)
到
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, (int)System.currentTimeMillis(), notificationIntent, PendingIntent.FLAG_ONE_SHOT);
答案 1 :(得分:0)
你必须改变这一行
notificationManager.notify(Unique_Integer_Number, notification);
替换为
public class Test {
// A normal (non-static) initializer does not have the problem
static {
try {
System.out.println("initializer start");
// --- Works
System.out.println("\nanonymous inner-class: Print.print");
EventQueue.invokeAndWait(new Runnable() {
@Override
public void run() {
Print.print();
}
});
// --- Works
System.out.println("\nmethod ref: Print.print");
EventQueue.invokeAndWait(Print::print);
// --- Hangs forever
System.out.println("\nlambda: Print.print");
EventQueue.invokeAndWait(() -> Print.print());
System.out.println("\ninitializer end");
} catch (Exception e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
new Test();
}
}
唯一整数表示您必须设置永不重复的整数值。例子0,1,2,3,4,5,.... !!!!