Question

我想打印从＆＃34; ajax＆＃34;在jwplayer javascript中。帮助我，我是javascript的新手。请帮我！抱歉我的英语不好。

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script src="/a/jwplayer.js" type="text/javascript"></script>
<script type="text/javascript">jwplayer.key="key";</script>
<div id="my-video">Loading ...</div>
<script>
    function loadPlayer(link){  
        var data = 'zing=' + link;
        $.ajax({
            type: "POST",
            url: "http://localhost/a/zing.php",
            data: data,
            success: function (getlink){jwplayer("my-video").setup({
                getlink, 
                image: "http://content.jwplatform.com/thumbs/Wf8BfcSt-640.jpg",
                width: "580",
                height: "370",
                primary: "html5",
                advertising: { 
                    client: "vast",
                    schedule: {"myAds":{"offset":"15","tag":"http://www.adotube.com/php/services/player/OMLService.php?avpid=oRYYzvQ&platform_version=vast20&ad_type=linear&groupbypass=1&HTTP_REFERER=http://www.longtailvideo.com&video_identifier=longtailvideo.com,test"}}
                }
            });}  
        });    
    }
</script>
<script>loadPlayer('http://tv.zing.vn/video/Date-a-Live-II-Tap-10-END/IWZA7BIW.html');</script>

Answer 1

您的问题就在您传递给init的{{1}}的对象中：

jwPlayer.setup

可能，这是你在找什么？

success: function (getlink){
  jwplayer("my-video").setup({
    getlink, // This is wrong. There must be some name of the parameter.

打印从＆＃34;获得的数据ajax＆＃34;在jwplayer javascript中

1 个答案: