如何将此SQL语句转换为PostgreSQL？

Question

我有一个不能在PostgreSQL服务器上运行的MySQL语句。

这是最初的MySQL查询：

SELECT count(*) AS howmany 
FROM members 
WHERE member_status =1 
AND member_sex = 'male' 
AND (YEAR( '2015-12-31' ) - YEAR( member_birthdate ) ) - 
    ( RIGHT( '2015-12-31', 5 ) < RIGHT( member_birthdate, 5 ) ) 
BETWEEN 27 AND 40;

这是我的方法：

SELECT COUNT(*) AS howmany FROM members
WHERE member_status =1 
AND member_sex ='male'
AND (EXTRACT(YEAR FROM '2015-12-31'::date) - EXTRACT(YEAR FROM member_birthdate)) 
BETWEEN 27 AND 40;

目标是，我想知道在2015-12-31的排位日期有多少会员年龄在27到40岁之间。 我不知道如何转换查询的右侧部分。

Answer 1

您可以使用AGE功能：

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          // get all article details generated by the back-end and add it to he grid
        });