Question

所以我正在尝试使用setText函数将文本从parseobject添加到TextView。我已经将我想添加的内容转换为字符串，但程序一直在崩溃，我没有找到其他人遇到这个问题所以我想我会发布在这里。

无论如何，这里是有问题的代码：

String text = (String)object.get("Text");
            Log.d("Recept", "text: " + text);
            int time = (int)object.get("Time");
            Log.d("Recept", "time: " + time);
            ParseFile image = (ParseFile)object.get("Picture");

            TextView recipeText = (TextView) findViewById(R.id.recipeText);
            recipeText.setText(text);

            TextView recipeTime = (TextView) findViewById(R.id.recipeTime);
            recipeTime.setText(time);

            Log.d("Recept", "The text was fine");

            ParseImageView recipeImage = (ParseImageView) findViewById(R.id.recipeImage);
            recipeImage.setParseFile(image);

日志记录所有内容，“文本很好”并返回我想要添加的字符串，所以我知道在此之前代码没有任何可疑之处。

我将在此之前添加部分，以防万一：

public class RecipePage extends AppCompatActivity{

//ListView lv;
/**
 * ATTENTION: This was auto-generated to implement the App Indexing API.
 * See https://g.co/AppIndexing/AndroidStudio for more information.
 */
private GoogleApiClient client;

@Override
protected void onCreate(Bundle savedInstanceState) {

    //ParseQueryAdapter<ParseObject> mainAdapter;

    Log.d("Recept", "Recipe on it's way!");
    super.onCreate(savedInstanceState);
    setContentView(R.layout.recipe_page);
    Log.d("Recept", "I made it in!");


    //int key2 = 2;
    String key = getIntent().getStringExtra("key");
    String label = getIntent().getStringExtra("Title");
    Log.d("Recept", "The found key was: " + key);
    //lv = (ListView) findViewById(R.id.listView2);
    setTitle(label);

    //Begin search
    ParseQuery<ParseObject> query = ParseQuery.getQuery("Recept");
    query.getInBackground(key, new GetCallback<ParseObject>() {
        public void done(ParseObject object, ParseException e) {
            Log.d("Recept", "I got this far");
            if (e == null) {
                Log.d("Recept", "I'm happy!");
            } else {
                Log.d("Recept", "Error, something went wrong: " + e);
            }
            String text = (String)object.get("Text");
            Log.d("Recept", "text: " + text);
            int time = (int)object.get("Time");
            Log.d("Recept", "time: " + time);
            ParseFile image = (ParseFile)object.get("Picture");

            TextView recipeText = (TextView) findViewById(R.id.recipeText);
            recipeText.setText(text);

            TextView recipeTime = (TextView) findViewById(R.id.recipeTime);
            recipeTime.setText(time);

            Log.d("Recept", "The text was fine");

            ParseImageView recipeImage = (ParseImageView) findViewById(R.id.recipeImage);
            recipeImage.setParseFile(image);
        }
    });

对不起日志，使用它们尝试进行故障排除。

Answer 1

所以我发现问题是

recipeTime.setText(time);

不起作用，因为我试图传递一个int应该是一个字符串。而是写recipeTime.setText(time + "");。 :)

Answer 2

替换 String text =（String）object.get（“Text”）;

要 String text = object.getString（“Text”）;

我希望这会对你有所帮助。

将Textview.setText（）与parseobjects一起使用

2 个答案: