如何测试给定的String是否是Java中的回文,而不使用任何方法为我做这一切?
答案 0 :(得分:6)
String palindrome = "..." // from elsewhere
boolean isPalindrome = palindrome.equals(new StringBuilder(palindrome).reverse().toString());
答案 1 :(得分:5)
public boolean checkPalindrome(string word){
for(int i=0 ; i < word.length()/2;i++)
{
if(word.charAt(i) ! = word.charAt(word.length()-1-i))
return false;
}
return true;
}
答案 2 :(得分:0)
Noel的解决方案实际上更好。但如果是作业,你可能想要这样做:
public static boolean isPalindrome(String word) {
int left = 0;
int right = word.length() -1;
while (left < right) {
if (word.charAt(left) != word.charAt(right))
return false;
left++;
right--;
}
return true;
}
答案 3 :(得分:0)
Java就地回文检查:
public static final boolean isPalindromeInPlace(String string) {
char[] array = string.toCharArray();
int length = array.length-1;
int half = Math.round(array.length/2);
char a,b;
for (int i=length; i>=half; i--) {
a = array[length-i];
b = array[i];
if (a != b) return false;
}
return true;
}
答案 4 :(得分:-2)
String str="iai";
StringBuffer sb=new StringBuffer(str);
String str1=sb.reverse().toString();
if(str.equals(str1)){
System.out.println("polindrom");
} else {
System.out.println("not polidrom");
}