Question

我正在使用Json.Net框架，我正在尝试使用一种方法将多个Json字符串转换为不同的对象来实现它。

要创建存储Json数据的对象，我正在使用此website。

到目前为止，我已经设法有一个方法来转换一个对象（在本例中为RootObject），代码如下：

public class WebService
{
    protected string jsonstring;

    // Other code

    // Method
    public RootObject stringToObject(){
        return JsonConvert.DeserializeObject<RootObject>(this.jsonstring);
    }
}

// Object
public class RootObject
{
    public string id { get; set; }
    public string name { get; set; }
    public string title { get; set; }
}

// Usage
WebService ws = new WebService ("http://example.com/json_string.json");
RootObject data = ws.stringToObject ();

问题是我需要将另外两个对象转换为Json字符串：

public class RootObject2
{
    public string id { get; set; }
    public string menu_id { get; set; }
    public string language { get; set; }
    public string title { get; set; }
}

public class RootObject3
{
    public string id { get; set; }
    public string menu_id { get; set; }
    public string position { get; set; }
    public string active { get; set; }
}

我尝试将方法返回类型更改为泛型类型，但它不起作用：

public object stringToObject(){
    return JsonConvert.DeserializeObject<object>(this.jsonstring);
}

如何将方法返回类型设置为动态，以便我可以执行以下操作：

WebService ws = new WebService ("http://example.com/json_string.json");
RootObject data = ws.stringToObject ();

WebService ws2 = new WebService ("http://example.com/json_string2.json");
RootObject2 data2 = ws2.stringToObject ();

WebService ws3 = new WebService ("http://example.com/json_string3.json");
RootObject3 data3 = ws3.stringToObject ();

Answer 1

为什么不让function fold(arr1, arr2) { var res = []; var currIndex = 0 var otherIndex = 0 var curr = arr1 var other = arr2 var i = 0; function switchVal() { var tmpIndex = otherIndex var tmp = other otherIndex = currIndex other = curr curr = tmp currIndex = tmpIndex } do { var indexInOther = other.indexOf(curr[currIndex], otherIndex) if (indexInOther >= 0) { var prevItems = other.slice(otherIndex, indexInOther + 1) res = res.concat(prevItems) otherIndex = indexInOther + 1 currIndex++ switchVal() } else if (currIndex < curr.length) { res.push(curr[currIndex]) currIndex++ } else { switchVal() } } while(currIndex < curr.length || otherIndex < other.length) return res }成为generic？

WebService

然后做

public class WebService<T>
{
    protected string jsonstring;

    // Other code

    // Method
    public T stringToObject(){
        return JsonConvert.DeserializeObject<T>(this.jsonstring);
    }
}

或者，如果您愿意，可以将var ws = new WebService<RootObject>("http://example.com/json_string.json"); var data = ws.stringToObject ();设为通用：

stringToObject

并做：

public class WebService
{
    protected string jsonstring;

    // Other code

    // Method
    public T stringToObject<T>(){
        return JsonConvert.DeserializeObject<T>(this.jsonstring);
    }
}

使用一种方法

1 个答案: