Powershell获取文件中花括号之间的所有字符串

Question

Filecontent = "Hello this is {{Santa}} from far-far-away coming to your {{country}}.

I like {{world}} with lot of {{Green}}.
You always made me feel {{Happy}} <Testing>"

我想得到结果：

Santa
country
Green
Happy

我尝试使用powershell + regex：(?<=.*{{)\w+?(?=}}.*)但是只有一个花括号{{xxx}}的实例才能得到我。

谢谢

Answer 1

PS D:\> $Filecontent = "Hello this is {{Santa}} from far-far-away coming to your {{country}}.

I like {{world}} with lot of {{Green}}.
You always made me feel {{Happy}} <Testing>"

PS D:\> [Regex]::Matches($filecontent, '(?<={{)(.*?)(?=}})') | Select -ExpandProperty Value

Santa
country
world
Green
Happy

正则表达式'(?<={{)(.*?)(?=}})'测试的位置：左侧{{，右侧}}，捕捉中间的所有内容 - 非贪婪（保留在一个括号对内）

Answer 2

尝试这样的事情：

final Cursor mCursor = getContentResolver().query(
        MediaStore.Audio.Albums.EXTERNAL_CONTENT_URI, // Uri
        new String[]{                                 // String[] projection (columns)
                MediaStore.Audio.Albums.ALBUM_ART,
                MediaStore.Audio.Albums.ARTIST,
                MediaStore.Audio.Albums.ARTIST,
                MediaStore.Audio.Albums.NUMBER_OF_SONGS,
                MediaStore.Audio.Albums.ALBUM_KEY
        },
        MediaStore.Audio.Albums._ID + " IN(?,?)",           // String selection
         new String[]{"16","25"},                                  // String[] selectionArgs
        null,                                         // sortOrder
        null                                          // CancellationSignal
);