Question

我有这个＆＃34;简单＆＃34;问题：我输入2个int数字，我必须按降序输出它们。

#include <stdio.h>
#include <iostream>

int fnum()
{
    int NUM;
    scanf("%d",&NUM);
    return NUM;
}

void frisultato(int x,int y)
{
    if (x>y)
    {
            printf("%d",x);
            printf("%d",y);
    }
    else
    {
            printf("%d",y);
            printf("%d",x);
    }

    return;
}

int main()
{    
      int A,B;     
      A=fnum;
      B=fnum;

      frisultato(A,B);
}

我在

收到错误

A=fnum;
B=fnum;

我的编译器说：从int（*）（）无效转换为int。

这是我第一次使用功能，有什么问题？谢谢！

米开朗基罗。

Answer 1

  A=fnum;
  B=fnum;

您实际上并未在此处调用函数fnum。您正在尝试将指向该函数的指针分配给int变量A和B。

要调用该函数，请执行以下操作：

  A=fnum();
  B=fnum();

Answer 2

很抱歉，但由于您似乎是编程新手，我无法帮助您重构/评论您的代码：

#include <stdio.h>
#include <iostream>

int fnum()
{
    int num; 
    scanf("%d",&num);
    return num;
}

void frisultato(int x, int y)
{
    if (x>y)
    {
        printf("%d",x);
        printf("%d",y);
    }
    else
    {
        printf("%d",y);
        printf("%d",x);
    }

    /* No need to return in void */
}

int main()
{    

    /*
        Variables in C are all lowercase. 

        UPPER_CASE is usually used for macros and preprocessor directives
        such as 

        #define PI 3.14 
    */
    int a, b;
    a = fnum(); //Function calls always need parenthesis, even if they are empty
    b = fnum();

    frisultato(a, b);

    /*
        Your main function should return an integer letting whoever 
        ran it know if it was successful or not. 

        0 means everything went well, anything else means something went wrong.
    */
    return 0;
}

另外，请勿在StackOverflow问题上签名。

使用函数从int *到int的转换无效

2 个答案: