Question

import re
numlist = list()
*total = 0*
handle = open('test.txt')
for line in handle:
    line = line.rstrip()
    x = re.findall('([0-9]+)', line)
    if len(x) > 0:
    *for nums in x:
        numlist.append(nums)
        value = int(nums)
        total = total+value

打印（总）*

test.txt文件的示例：

jhjkhjhhjkhjh 5678 kjhlkjsd lkjaksd 6578 8765 hnhdtriusnfasdasdweefgdf dfdf dfdfdfdferse5667 9876gjshdi ksdhsks k6453jjhkkk 9087jjskldnjck kjshhdck 9877 khhgjnh 8532 jnhyg 7634iutr jhgpiunegjd wert 1234 kjhg 4567 kjh b 0987 jhggebndueh nhergsus df 9987 7654 0129kk jhikhhhgkjhhjiiksyehf 9876 ijh kjhgj 1234

Answer 1

如果您只想获取所有数字并将它们相加，那么如果删除星号并正确缩进，则代码可以正常工作。缩进在python中至关重要。不知道为什么星号在那里？

import re

numlist = list()
total = 0
handle = open('test.txt')
for line in handle:
    line = line.rstrip()
    x = re.findall('([0-9]+)', line)
    if len(x) > 0:
        for nums in x:
            numlist.append(nums)
            value = int(nums)
            total = total+value
print(total)

我会稍微更改一下，你没有提到你想要使用numlist的内容，所以我在下面的代码中删除了它。

import re

total = 0
with open('test.txt') as handle:
    for line in handle:
        x = re.findall('([0-9]+)', line)
        for num in x:
            total += int(num)
print(total)

Python3.5如何将字符串列表转换为int所以我可以总结一下？

1 个答案: