如果整数不均匀（奇数），我想获得前一个数字，否则我想保留当前数字。例如。如果Connection.Response response = Jsoup.connect("http://www.itatonline.in:8080/itat/jsp/runBirt2.jsp?subAction=showReoprt&__report=CaseDetails1_DELHI.rptdesign&searchWhat=searchByAssName&Serial%20No=&Appeal%20No=&Assessee%20Name=&AssType=DontKnow&appealDate=&Bench=AGR").method(Method.GET).timeout(30000).execute();
String url = "http://www.itatonline.in:8080/itat/jsp/runBirt2.jsp?subAction=showReoprt&__report=CaseDetails1_DELHI.rptdesign&searchWhat=searchByAssName&Serial%20No=&Appeal%20No=&Assessee%20Name=k&AssType=DontKnow&appealDate=&Bench=AGR&__sessionId=20151210_231624_579";
String rawData = "<soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/>"
+ "<soap:Body><GetUpdatedObjects xmlns=\"http://schemas.eclipse.org/birt\">"
+ "<Operation><Target><Id>Document</Id><Type>Document</Type></Target><Operator>GetPage</Operator><Oprand><Name>Appeal No</Name><Value></Value></Oprand><Oprand><Name>__isdisplay__AppealNo</Name><Value></Value></Oprand><Oprand><Name>Serial No</Name><Value></Value></Oprand><Oprand><Name>__isdisplay__Serial No</Name><Value></Value></Oprand><Oprand><Name>Assessee Name</Name><Value>k</Value></Oprand><Oprand><Name>__isdisplay__Assessee Name</Name><Value>k</Value></Oprand><Oprand><Name>searchWhat</Name><Value>searchByAssName</Value></Oprand><Oprand><Name>__isdisplay__searchWhat</Name><Value>searchByAssName</Value></Oprand><Oprand><Name>AssType</Name><Value>DontKnow</Value></Oprand><Oprand><Name>__isdisplay__AssType</Name><Value>DontKnow</Value></Oprand><Oprand><Name>appealDate</Name><Value></Value></Oprand><Oprand><Name>__isdisplay__appealDate</Name><Value></Value></Oprand><Oprand><Name>Bench</Name><Value>AGR</Value></Oprand><Oprand><Name>__isdisplay__Bench</Name><Value>AGR</Value></Oprand><Oprand><Name>__page</Name><Value>1</Value></Oprand><Oprand><Name>__svg</Name><Value>true</Value></Oprand><Oprand><Name>__page</Name><Value>1</Value></Oprand><Oprand><Name>__taskid</Name><Value>2015-11-9-23-16-22-34</Value></Oprand></Operation></GetUpdatedObjects></soap:Body></soap:Envelope>";
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
//add reuqest header
con.setRequestMethod("POST");
con.setRequestProperty("Content-Type", "text/xml; charset=UTF-8");
con.setRequestProperty("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");
con.setRequestProperty("Cookie", response.cookies().toString().replaceAll("[{}]", ""));
con.setRequestProperty("Host", "www.itatonline.in:8080");
con.setRequestProperty("Referer", "http://www.itatonline.in:8080/itat/jsp/runBirt2.jsp?subAction=showReoprt&__report=CaseDetails1_DELHI.rptdesign&searchWhat=searchByAssName&Serial%20No=&Appeal%20No=&Assessee%20Name=k&AssType=DontKnow&appealDate=&Bench=AGR");
con.setRequestProperty("SOAPAction", "");
con.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.3; rv:42.0) Gecko/20100101 Firefox/42.0");
con.setRequestProperty("X-Prototype-Version", "1.4.0");
con.setRequestProperty("X-Requested-With", "XMLHttpRequest");
con.setRequestProperty("request-type", "SOAP");
// Send post request
con.setDoOutput(true);
OutputStreamWriter w = new OutputStreamWriter(con.getOutputStream(), "UTF-8");
w.write(rawData);
w.close();
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer resp = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
resp.append(inputLine);
}
in.close();
System.out.println(resp);
，我想将x = 3分配给2，如果x，则不会发生任何事情。
目前，我执行以下操作：x = 4，但我听说该划分计算费用昂贵。 x = (x/2)*2是否会优化此表达式？我正在使用-O3编译器。 c++ (Ubuntu 4.8.4-2ubuntu1~14.04) 4.8.4是x。
答案 0 :(得分：2)
尝试以下
x &= ~1;
我认为x被声明为具有类型int。否则，如果类型x的等级大于int类型的等级，则应使用变量x类型的整数文字。