Question

$date2 = $row['returnbefore'];

$date1 = date('Y/m/d');

$diff = abs(strtotime($date1) - strtotime($date2));

$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

$final = ($days * 10) ;

echo $final;

我想做一个图书馆系统，当用户返回图书时会检查当前日期之间的返回日期，并计算一个罚款给用户，每天乘以10。我离开了什么？我想设置当前时间是我的电脑时间，所以我可以测试它

Answer 1

使用DateTime和DateInterval完成这是一个相当简单的问题。

$now = new DateTime();
$dueDate = new DateTime($row['returnbefore']);

$lateInterval = $now - $dueDate;
$daysLate = $lateInterval->format('d');
$fine = $daysLate > 0 ? intval(floor($daysLate)) * 10 : 0; // This means that you are not charged for a late day until the end of the day

计算两天之间并计算罚款

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