Question

我在使用SQLSRV执行存储过程时遇到跟随错误。

Array ( 
  [0] => Array ( 
          [0] => 42000 
          [SQLSTATE] => 42000 
          [1] => 102 
          [code] => 102 
          [2] => [Microsoft]
          [ODBC Driver 11 for SQL Server] 
          [SQL Server] Incorrect syntax near '='. 
          [message] => 
               [Microsoft]
                   [ODBC Driver 11 for SQL Server]
                      [SQL Server]Incorrect syntax near 'r'. ) 
                           [1] => Array ( [0] => 42000 [SQLSTATE] => 42000 [1] => 8180 [code] => 8180 [2] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]Statement(s) could not be prepared. [message] => [Microsoft][ODBC Driver 11 for SQL Server][SQL Server]Statement(s) could not be prepared. ) )

$tsql_callSP = "EXEC usp_u_social_twitter var_tweet = ?, var_screenname = ?, var_maxid = ?, var_link = ?, varid = ?";

我使用的代码如下

$tsql_callSP = "EXEC usp_u_social_twitter var_tweet = ?, var_screenname = ?, var_maxid = ?, var_link = ?, varid = ?";

$stmt3 = sqlsrv_prepare( $conn, $tsql_callSP, array(&$tweet, &$screenname, &$maxid, &$link, &$id));

我在这里缺少什么语法。这里列出的这些变量名称不是真正的。但我在这里缺少一些语法...

如果我提供正常的更新查询...具有相同的变量名...

，代码可以正常工作

请帮助我...提前致谢... 这是什么正确的语法...即使在堆栈中也无法找到示例程序。

Answer 1

你错过了＆＃34; @＆＃34;在存储过程的参数的开头。它应该是：

$tsql_callSP = "EXEC usp_u_social_twitter @var_tweet = ?, @var_screenname = ?, @var_maxid = ?, @var_link = ?, @varid = ?";

用于更新查询的EXEC存储过程的语法

1 个答案: