Question

我试图找到一个sting的URL。我想检查字符串是否包含任何URL。

为此我写了代码：

function get_url_from_string(str) {
        var searchText = str,
          urls = searchText.match(/\b(http|https)?(:\/\/)?(\S*)\.(\w{2,4})\b/ig);
         for (var i = 0, il = urls.length; i < il; i++) {
            var ur=urls[i];
        }
        return ur;

    }

但它只返回带有任何参数的URL。例如，如果我通过：

您好检查https://www.youtube.com/watch?v=eHOc-4D7MjY

它只给我https://www.youtube.com

我想获得完整的网址。我不知道正则表达式。请帮忙。谢谢

Answer 1

试试这个 -

/\b(https?:\/\/)?([\da-z\.-]+)\.([a-z\.]{2,6})([\/\w \.-]*)*\/?\s/

Answer 2

试试这个对我来说效果很好。

      var url_regex = /(?:(?:https?|ftp):\/\/)?(?:\S+(?::\S*)?@)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?/gi;
      var text = "some text string here!!";
      var urls_array = [];
      while ((urls = url_regex.exec(text)) !== null) {
                            urls_array.push(urls[0]);
                    }

此代码用于我的项目

Answer 3

function get_url_from_string(str) {
 
        var searchText = str,
          urls = searchText.match(/\b(http|https)?(:\/\/)?(\S*)\.(\w{2,4})?(.*)\b/ig);
         for (var i = 0, il = urls.length; i < il; i++) {
            var ur=urls[i];
        }
  alert(ur);
  
        return ur;
  }

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="x" onclick="get_url_from_string('https://www.youtube.com/watch?v=eHOc-4D7MjY')">click here
</button>

使用jQuery从字符串中获取完整的URL

3 个答案: