MYSQL查询显示执行错误

Question

我试图从我的数据库中选择所有已经访问过我网站的ips，不止一次，至少每天一次，从本月开始，但我的SQL查询显示错误。我做错了什么？

SELECT ip,COUNT(ip) AS matches
FROM ipAll
WHERE DATE LIKE  '%-12-%'
HAVING matches > '1'
GROUP BY ip

错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP BY ip

Answer 1

HAVING来自GROUP BY：

SELECT ip, COUNT(ip) AS matches
FROM ipAll
WHERE DATE LIKE  '%-12-%'
GROUP BY ip
HAVING matches > 1;

但是，您应该更像这样编写查询：

SELECT ip, COUNT(ip) AS matches
FROM ipAll
WHERE MONTH(DATE) = 12
GROUP BY ip
HAVING matches > 1;

不要在日期上使用LIKE，因为使用本地国际化设置将日期转换为字符串（隐式）。这些可能会改变，只是打破代码。另外，不要在需要数字的地方使用字符串常量。

Answer 2

错误是因为根据mysql文档，having子句必须在group by子句之后才能使用。

所以你的查询必须看起来像这样

SELECT ip,COUNT(ip) AS matches FROM ipAll WHERE DATE LIKE  '%-12-%' GROUP BY ip HAVING matches > '1'

Answer 3

SELECT ip, COUNT(ip) AS matches
FROM ipAll
WHERE DATE LIKE  '%-12-%'
GROUP BY ip
HAVING matches > 1;