What would be the most efficient way to multiply (element-wise) a 2D tensor (matrix):
x11 x12 .. x1N
...
xM1 xM2 .. xMN
by a vertical vector:
w1
...
wN
to obtain a new matrix:
x11*w1 x12*w2 ... x1N*wN
...
xM1*w1 xM2*w2 ... xMN*wN
To give some context, we have M
data samples in a batch that can be processed in parallel, and each N
-element sample must be multiplied by weights w
stored in a variable to eventually pick the largest Xij*wj
for each row i
.
答案 0 :(得分:39)
执行此操作的最简单代码依赖于tf.multiply()
* 的广播行为,该行为基于numpy's broadcasting behavior:
x = tf.constant(5.0, shape=[5, 6])
w = tf.constant([0.0, 1.0, 2.0, 3.0, 4.0, 5.0])
xw = tf.multiply(x, w)
max_in_rows = tf.reduce_max(xw, 1)
sess = tf.Session()
print sess.run(xw)
# ==> [[0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
# [0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
# [0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
# [0.0, 5.0, 10.0, 15.0, 20.0, 25.0],
# [0.0, 5.0, 10.0, 15.0, 20.0, 25.0]]
print sess.run(max_in_rows)
# ==> [25.0, 25.0, 25.0, 25.0, 25.0]
* 在早期版本的TensorFlow中,tf.multiply()
被称为tf.mul()
。您还可以使用*
运算符(即xw = x * w
)执行相同的操作。