Question

我想在每个div中显示倒计时。现在我从数据库中获取秒数并存储在data-countdown属性中，然后使用以下js代码进行倒计时。只有第一个div每秒更改一次，而其他值不会更改。这是小提琴： this issue

//imagine this line of code in every loop of a for loop so $remaining will be different
<div style="font-size: 25px; color:#e3b40b ; font-weight: 600;" data-countdown="'.$remaining.'"><i class="fa fa-spinner fa-pulse"></i></div>

这里是js代码

$('[data-countdown]').each(function() {

finalDate = $(this).data('countdown');
var $this = $(this);
timeout = null;
time = null;
startCountdown($this,finalDate, 1000, end);

function startCountdown(display,timen, pause, callback) {
    time = timen;
    display.html(timen);

    if (timen == 0)
        callback();
    else {
        clearTimeout(timeout);
        timeout = setTimeout(function () {
            startCountdown(display,timen - 1, pause, callback)
        }, pause);
    }
}

function end() {
    alert();
}
});

Answer 1

如果在不使用var关键字的情况下声明变量，则需要创建全局变量。因此，倒计时的每个实例都会覆盖先前的finalDate，timeout和time值。尝试在每个行之前添加var，它应该做你需要的。即：

var finalDate = $(this).data('countdown');
var $this = $(this);
var timeout = null;
var time = null;
startCountdown($this,finalDate, 1000, end);

Answer 2

您也可以在常规Javascript而不是jQuery中执行此操作...

var countdownDivs = document.querySelectorAll('div[data-countdown]');

function end() {
    alert();
}
function countdown(display, timen, pause, callback) {
    display.innerHTML = timen;

    if (timen == 0) callback();
    else {
        display.timeout;
        clearTimeout(display.timeout);
        display.timeout = setTimeout(function () {
            countdown(display, timen - 1, pause, callback)
        }, pause);
    }
}

for(var i = countdownDivs.length>>>0; i--;){
    countdown(countdownDivs[i], countdownDivs[i].dataset.countdown, 1000, end);
}

div[data-countdown]{
    font-size:25px;
    color:#e3b40b;
    font-weight:600;
}

<div data-countdown="12312312"></div>

<div data-countdown="555555"></div>

<div data-countdown="95695"></div>

div的单独倒计时

2 个答案: