Question

我想删除删除SQL数据库中图像的链接。我的任务是创建一个不使用JavaScript的删除确认选项。

require_once("photoalbum-common.php");

$pdo = connect();

if ( isset( $_GET['deletionid'])) {
  $errorMessage = deletePhotograph( $pdo, $_GET['deletionid']);
  if ( $errorMessage != "") {
    print "<div class='errormessage'>$errorMessage</div>\n";
  } else {
    print "<div class='message'>Image deleted.</div>\n";    
  }
}

以下代码位于“photoalbum-common.php”。

<?php

function deletePhotograph( $pdo, $deletionid) {
  $errorMessage = "";
  // retrieve name of image file so we can delete it
  $stmt = $pdo->prepare("SELECT `image` FROM `photographs` WHERE `photoid`=?");
  $stmt->execute( array( $deletionid));  
  $rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
  if ( count( $rows) == 1) {
    // delete file
    unlink( "images/".$rows[0]['image']);    
    // delete database record
    $stmt = $pdo->prepare("DELETE FROM `photographs` WHERE `photoid`=?");
    $stmt->execute( array( $deletionid));  
    $affected_rows = $stmt->rowCount();    
  } else if (count( $rows) > 1) {
    $errorMessage .= "ID matches more than one record. ";
  } else {
    $errorMessage .= "ID not found: nothing to delete. ";
  }
  return $errorMessage;
}

?>

Answer 1

使用类似的东西。插页式页面，接受GET请求：

获取请求 GET /delete.php?id=123

你确定要删除吗？

POST请求 POST /delete.php?id=123

执行PDO。

您应该为PHP编写代码。如果答案还不够，那我们就去吧：

<?php
  if (count($_POST)) {
    // POST Request
    deletePhotograph();
  } else {
    // GET Request
    ?>
    <p>Are you sure you wanna delete?</p>
    <!-- Empty action will POST to the same page. -->
    <form action="" method="POST"><input type="submit" value="I confirm, Delete" /></form>
    <?php
  }
?>

删除仅使用PHP

1 个答案: