Question

我尝试使用Select Option传递数据，而不是要求用户手动输入。但是，我无法让它传递价值。我有一个错误消息，指出缺少的值是一个预定义的消息：

Please Enter The Issuing State for your Drivers License。

不确定我哪里出错了。如果有人愿意指出我正确的方向。

PHP

if (empty($_POST['driverslicensestate'])) { $error[] = 'Please Enter The Issuing State for your Drivers License ';} 
    else { $driverslicensestate = $_POST['driverslicensestate']; }

HTML

<div class="elements">
        <select id="driverslicensestate" name"driverslicensestate">
            <option selected value="-1">Select Drivers License State</option>
            <option id="driverslicensestate" name="driverslicensestate" value="AL">Alabama</option>
            <option id="driverslicensestate" name="driverslicensestate"  value="AK">Alaska</option>
            <option id="driverslicensestate" name="driverslicensestate"  value="AZ">Arizona</option>
            <option id="driverslicensestate" name="driverslicensestate"  value="AR">Arkansas</option>
            <option id="driverslicensestate" name="driverslicensestate"  value="CA">California</option>
            <option  id="driverslicensestate" name="driverslicensestate" value="CO">Colorado</option>
            <option id="driverslicensestate" name="driverslicensestate"  value="CT">Connecticut</option>
            <option  id="driverslicensestate" name="driverslicensestate" value="DE">Delaware</option>
...
    </select>   
</div>

使用只使用文本字段时工作得很好。

<input type="text" placeholder="Drivers License #" id="driverslicense" name="driverslicense" size="25" />

Answer 1

等于！

[self managedObjectContext]

为什么要为选项添加name属性？我想，只是价值就足够了！

Answer 2

添加'='以选择

<select id="driverslicensestate" name="driverslicensestate">

选择＆gt;选项＆gt;发布价值问题

2 个答案: