我正在使用＆＃34; std :: stringstream＆＃34;，用于转换＆＃34; long＆＃34;值为＆＃34;十六进制字符串＆＃34;，以便在代码中进一步使用。
以下代码段：
void initDisplayVariant(){
...
/// integer value to hex-string
std::stringstream sstream;
sstream << "0x"
<< std::setfill ('0') << std::setw(2)
<< std::hex << (int)frntDispVariant;
std::string frntDispVariantHex = sstream.str();
sstream.clear(); //clears out the stream-string
...
}
但是，valgrind列出了＆＃34;可到达泄漏的位置＆＃34;。
...
==6736== 0 bytes in 1 blocks are still reachable in loss record 1 of 143
==6736== at 0x4024045: operator new[](unsigned int) (vg_replace_malloc.c:299)
==6736== by 0x5232570: std::__numpunct_cache<char>::_M_cache(std::locale const&) (in /usr/lib/libstdc++.so.6.0.14)
==6736== by 0x5236684: std::ostreambuf_iterator<char, std::char_traits<char> > std::num_put<char, std::ostreambuf_iterator<char, std::char_traits<char> > >::_M_insert_int<long>(std::ostreambuf_iterator<char, std::char_traits<char> >, std::ios_base&, char, long) const (in /usr/lib/libstdc++.so.6.0.14)
==6736== by 0x523678D: std::num_put<char, std::ostreambuf_iterator<char, std::char_traits<char> > >::do_put(std::ostreambuf_iterator<char, std::char_traits<char> >, std::ios_base&, char, long) const (in /usr/lib/libstdc++.so.6.0.14)
==6736== by 0x5241B43: std::ostream& std::ostream::_M_insert<long>(long) (in /usr/lib/libstdc++.so.6.0.14)
==6736== by 0x5241CB4: std::ostream::operator<<(int) (in /usr/lib/libstdc++.so.6.0.14)
==6736== by 0x808E76B: initDisplayVariant() (src.cpp:45)
...
由于流是方法本地的，并且不应该存在于方法范围之外（即使它在内部进行分配），因此报告泄漏的上下文不明确。
有任何线索或建议吗？