Question

我有一些用python烧写的代码，我有一个函数如下：

SELECT per.person_no,
  perbus.person_no,
  perbus.edit_dt,
  perbus.org_name,
  perbus.FIRST_NAME
FROM users.persons per
LEFT OUTER JOIN
  (SELECT ASSOC.edit_dt,
    PER_CONTACTS.PERSON_NO,
    PER_CONTACTS.PERSON_ID AS PER_ID,
    PER.EXTERNAL_PERSON_ID AS EXT_PER_ID,
    PER_CONTACTS.LNAME
    ||', '
    ||PER_CONTACTS.FNAME AS NAME,
    PER_CONTACTS.FNAME   AS FIRST_NAME,
    PER_CONTACTS.MNAME   AS MIDDLE_NAME,
    PER_CONTACTS.LNAME   AS LAST_NAME,
    ORG.ORG_NAME         AS ORG_NAME,
    T_ORG.ORG_ID         AS ORG_ID,
    T_ORG.ORG_DISPLAY_ID AS EXT_ORG_ID,
    ROW_NUMBER() OVER(PARTITION BY PER_CONTACTS.PERSON_ID ORDER BY ASSOC.edit_dt DESC) rn
  FROM USERS.PER_CONTACTS PER_CONTACTS
  LEFT OUTER JOIN USERS.PERSONS PER
  ON PER.PERSON_ID = PER_CONTACTS.PERSON_ID
  LEFT OUTER JOIN USERS.ASSOC ASSOC
  ON ASSOC.PERSON_ID = PER.PERSON_ID
  LEFT OUTER JOIN USERS.T_ORG T_ORG
  ON T_ORG.T_ORG_ID = ASSOC.T_ORG_ID
  LEFT OUTER JOIN USERS.ORG ORG
  ON ORG.ORG_ID                       = T_ORG.ORG_ID
  WHERE PER_CONTACTS.CONTACT_ROLE_LOV = 'EMPLOYEE'
  AND PER_CONTACTS.PERSON_NO         IN
    (SELECT PERSON_NO FROM USERS.QA_APPROVED
    )
  ORDER BY ASSOC.edit_dt DESC
  ) perbus ON perbus.PERSON_NO = PER.PERSON_NO
WHERE PER.PERSON_NO           IN
  (SELECT PERSON_NO FROM USERS.QA_APPROVED
  )
AND perbus.rn = 1;

但是这条消息不足以为我提供足够的信息。我只想打印传递给errorhandler的异常的回溯。有没有办法做这个简单的事情？

Answer 1

假设在sys仍然可以使用异常和回溯时从上下文中调用错误处理程序，您应该可以使用traceback.format_exc。

import traceback

@app.errorhandler(500)
def internal_error(exception):
    print "500 error caught"
    print traceback.format_exc()

Answer 2

我认为你可以这样解决：

import sys
import traceback

@app.errorhandler(500)
def internal_error(exception):
    print "500 error caught"
    etype, value, tb = sys.exc_info()
    print traceback.print_exception(etype, value, tb)

您可以打印回溯信息

如何只打印传递给python flask中的errorhandler函数的异常的简单回溯

2 个答案: