Question

drinks = ['cola', 'water', 'beer', 'wine']

drinks = raw_input ("What did you drink? " + print drinks)

所以，基本上我希望程序向用户显示问题，然后打印出可能的答案。用户应该将其中一个键入程序。我尝试了上面的代码，但它不起作用。在drinks之前打印raw_input没有意义。我想你也可以这样做：

drinks = ['cola', 'water', 'beer', 'wine']

drinks1 = raw_input("Hai, wanna have a look at the most popular drinks here?")
if drinks1 == "yes":
print drinks

drinks2 = raw_input("So, what did you drink?")

...但有没有比Python更简单的用户可以选择的列表？

提前感谢您的回答。

Answer 1

一个非常简单的解决方案可能是

 if (sLabel.text > 10) {

     // imgV.image = [UIImage imageNamed:@"small dot.png"];

    }

使用drinks = ['cola', 'water', 'beer', 'wine'] drink = raw_input ("What did you drink? %s" % ', '.join(drinks)) if drink in drinks: print('you chose ' + drink) else: print('invalid choice')从列表中删除字符串。

Answer 2

您可以使用strip和lower函数编写通用程序。其他一切看起来还不错。

drinks = ['cola', 'water', 'beer', 'wine']

user_input = raw_input("Hai, wanna have a look at the most popular drinks here?")

if user_input.strip().lower() == "yes":
   print drinks

drinks2 = raw_input("So, what did you drink?")

打印出Python列表

2 个答案: