我有以下PHP文件,我需要将where
条件添加到条件应该如下的select语句中:WHERE tbl_module.delete_time IS NUll
数据库中的表以tbl_
开头,而数组中没有tbl_
$json["status"] = "running";
$details[] = "started get_tables ";
// Include confi.php
include_once('confi.php');
//var_dump($_POST);
$request_body = file_get_contents('php://input');
// first store the given set of data to keep it for future analysis
$statement = "INSERT INTO tbl_archive (content) VALUES ('$request_body' );";
mysql_query($statement);
$input = json_decode($request_body, true);
// now check if valid user
$user = $input["user"];
$username = $user["username"];
$password = $user["password"];
if($password and $username){
$mySQLstring = "SELECT username, password, id FROM tbl_user where username = '$username' ;";
$json["statement"][] = $mySQLstring;
$qur = mysql_query($mySQLstring);
//var_dump ( $qur );
if ($qur){
$res = mysql_fetch_assoc($qur);
}
if ($res){
$json["res"] = $res;
if ($res["password"] == $password){
$json["username"] = $username;
$json["id"] = $res["id"];
$json["status"] = "ok";
$tables = array("class", "class_user", "module", "module_class", "module_user", "rating", "student", "student_class");
//$tables = array("class");
foreach($tables as $table){
$statement = "SELECT * FROM tbl_".{$table};
$qur = mysql_query($statement);
if ($qur){
while($r = mysql_fetch_array($qur, MYSQL_ASSOC)){
//var_dump($r);
//echo (json_encode($r));
$result[$table][] = $r;
}
}
}
$json = array("status" => "ok", "data" => $result);
}
}
}
@mysql_close($conn);
/* Output header */
header('Content-type: application/json');
echo json_encode($json);
?>
答案 0 :(得分:0)
您应该查看Official MySQL Documentation:
SELECT
[ALL | DISTINCT | DISTINCTROW ]
[HIGH_PRIORITY]
[MAX_STATEMENT_TIME = N]
[STRAIGHT_JOIN]
[SQL_SMALL_RESULT] [SQL_BIG_RESULT] [SQL_BUFFER_RESULT]
[SQL_CACHE | SQL_NO_CACHE] [SQL_CALC_FOUND_ROWS]
select_expr [, select_expr ...]
[FROM table_references
[PARTITION partition_list]
[WHERE where_condition]
所以WHERE
条件应该在FROM
之后。您应该能够轻松修改$statement
变量以包含它。