Question

我的错误就是这个，我有这些变量：

C:/romanchenko_test_task/static/first-style.css

的file_get_contents（$请求）;

所有这些变量都会自动填充，但是当我使用file_get_contents运行时，答案是这样的：

$request =  "https://xxxxx.xxx.com/2/delivery/request?";
    $request.=  "api_key=".$api_key."&";
    $request.=  "user_id=".$user_id."&";
    $request.=  "deliveery_type=".$delivery_type."&";
    $request.=  "route=E.+Pallares+y+&";
    $request.=  "street_number=110&";
    $request.=  "neighborhood=San Lucas&";
    $request.=  "locality=Distrito&";
    $request.=  "administrative_area_level_1=Distrito&";
    $request.=  "postal_code=04030&";
    $request.=  "country=Mexico&";
    $request.=  "latlng=".$latlng."&";
    $request.=  "destination-route=".$destination_route."&";
    $request.=  "destination-street_number=&";
    $request.=  "destination-neighborhood=&";
    $request.=  "destination-locality=".$destination_locality."&";
    $request.=  "destination-administrative_area_level=".$destination_administrative_area_level."&";
    $request.=  "destination-postal_code=".$destination_postal_code."&";
    $request.=  "destination-country=Mexico&";
    $request.=  "destination-latlng=".$d_latlng."&";
    $request.=  "customer_email=".$customer_email."&";
    $request.=  "customer_phone=".$customer_phone."&";
    $request.=  "notification_email=&";
    $request.=  "notes=".$notes."&";
    $request.=  "dispatch=True";

在我的error_log中检查，我看到网址已完成，但我不知道为什么会出现这些错误

Answer 1

我认为您希望对每个参数/值段中的值进行urlencode，如下所示：

$request = "https://www.site.tld/path/to/api?param=" . urlencode($value);

...等

Answer 2

您应该尝试发送gets as stream方法;

您可以在

获取更多信息

http://php.net/manual/en/function.file-get-contents.php

这将使用php提供的内置功能

使用file_get_content获取数据

2 个答案: