我试图记住如何处理遗产而撞墙。假设我们有一个名为Fruits的父/基类和名为Apples的子/派生类。苹果只与水果有所不同,因为它有一个额外的变量,称为数字。我们如何实现它,以便默认情况下Apples始终使用值" Apples"来调用父类构造函数。 (名称)和SNACK(类型)?
水果将如此实施(
Fruits::Fruits(string name, KIND type): myName(name), myKind(type)
{}
如何实施苹果,以便如果苹果被称为苹果(),它默认名称为"苹果"并键入SNACK,数字为5? 这是对的吗?
Apples::Apples() : Fruits("Apple", SNACK)
{
number = 5;
}
Apples::Apples(int num) : FoodItem("Pancakes", BREAKFAST )
{
}
答案 0 :(得分:1)
This way is correct:
Note: $email2 is array emails.
require 'smtp/PHPMailerAutoload.php';
$mail = new PHPMailer;
//$mail->SMTPDebug = 2; // Enable verbose debug output
$mail->isSMTP(); // Set mailer to use SMTP
$mail->Host = "localhost"; // Specify main and backup SMTP servers
$mail->SMTPAuth = true; // Enable SMTP authentication
$mail->Username = 'contacto@xxx.com'; // SMTP username
$mail->Password = 'password'; // SMTP password
$mail->SMTPSecure = 'ssl'; // Enable TLS encryption, `ssl` also accepted
$mail->SMTPKeepAlive = true; // SMTP connection will not close after each email sent, reduces SMTP overhead
$mail->Port = 465; // TCP port to connect to
$mail->CharSet = 'UTF-8';
$mail->setFrom('contacto@xxx.com', 'Website');
$mail->Subject = 'Se ha actualizado tu serie favorita';
$mail->AltBody = 'Para ver este mensaje, use un visor de email compatible con HTML!';
$mail->addReplyTo('contacto@xxx.com');
$mail->isHTML(true);
$mail->Body = 'The Body is HTML Code';
if($vtitle == "Existe") {
foreach($email2 as $email3)
{
$mail2 = clone $mail;
$mail2->addAddress(''.$email3.''); // Add a recipient
$envio = $mail2->send();
}
} else {
echo "El Capitulo no Existe";
}
if(!$envio) {
echo 'El Mensaje no ha podido enviarse.';
echo 'Error: ' . $mail2->ErrorInfo;
} else {
echo 'El Mensaje ha sido enviado.';
}
but this way would be better as it more readable and consistent:
Apples::Apples() : Fruits("Apple", BREAKFAST)
{
number = 5;
}
答案 1 :(得分:0)
我会尝试这些:
// Default value for number
Apples::Apples() : Fruits("Apple", SNACK), number(5)
{
}
// Caller specified value for number
Apples::Apples(int num) : FoodItem("Pancakes", BREAKFAST), number(num)
{
}