Question

Morning Guys，

我有一个从List下载并拥有公共属性的集合。 Xml序列化程序没有提升我的能力。列表项序列化很好。我尝试过XmlAttribute属性无济于事。你们有解决方案吗？

    public partial class MainWindow : Window
{
    public MainWindow()
    {
        InitializeComponent();
    }
    private void button1_Click(object sender, RoutedEventArgs e)
    {
        var people = new PersonCollection
        {
            new Person { FirstName="Sue", Age=17 },
            new Person { FirstName="Joe", Age=21 }
        };
        people.FavoritePerson = "Sue";

        var x = new XmlSerializer(people.GetType());
        var b = new StringBuilder();
        var w = XmlTextWriter.Create(b, new XmlWriterSettings { NewLineChars = "\r\n", Indent = true });
        x.Serialize(w, people);
        var s = b.ToString();
    }
}

[XmlRoot(ElementName="People")]
public class PersonCollection : List<Person>
{
    //DOES NOT WORK! ARGHHH
    [XmlAttribute]
    public string FavoritePerson { get; set; }    
}

public class Person
{
    [XmlAttribute]
    public string FirstName { get; set; }
    [XmlAttribute]
    public int Age { get; set; }
}

我收到以下xml

<?xml version="1.0" encoding="utf-16"?>
        <People xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
          <Person FirstName="Sue" Age="17" />
          <Person FirstName="Joe" Age="21" />
        </People>

我想得到这个

<?xml version="1.0" encoding="utf-16"?>
        <People FavoritePerson="Sue" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
          <Person FirstName="Sue" Age="17" />
          <Person FirstName="Joe" Age="21" />
        </People>

Answer 1

我继续通过实现IXmlSerializable来解决问题。如果存在更简单的解决方案，请发布它！

    [XmlRoot(ElementName="People")]
public class PersonCollection : List<Person>, IXmlSerializable
{
    //IT WORKS NOW!!! Too bad we have to implement IXmlSerializable
    [XmlAttribute]
    public string FavoritePerson { get; set; }

    public System.Xml.Schema.XmlSchema GetSchema()
    {
        return null;
    }
    public void ReadXml(XmlReader reader)
    {
        FavoritePerson = reader[0];            
        while (reader.Read())
        {
            if (reader.Name == "Person")
            {
                var p = new Person();
                p.FirstName = reader[0];
                p.Age = int.Parse( reader[1] ); 
                Add(p);
            }
        }
    }
    public void WriteXml(XmlWriter writer)
    {
        writer.WriteAttributeString("FavoritePerson", FavoritePerson);
        foreach (var p in this)
        {
            writer.WriteStartElement("Person");
            writer.WriteAttributeString("FirstName", p.FirstName);
            writer.WriteAttributeString("Age", p.Age.ToString());
            writer.WriteEndElement();            
        }
    }
}

Answer 2

这不是问题的答案，但我认为我会提出一个简化代码开发的建议。

将新的Add方法添加到PersonCollection类中：

public class PersonCollection : List<Person>, IXmlSerializable
{
...
    public void Add(string firstName, int age)
    {
        this.Add(new Person(firstName, age));
    }
...
}

然后，通过这样做，您可以将集合初始化程序语法简化为：

var people = new PersonCollection
{
    { "Sue", 17 },
    { "Joe", 21 }
};
people.FavoritePerson = "Sue";

Answer 3

如果你不介意必须包装所有列表函数，那么你可以将列表作为类的属性嵌入而不是从它派生。

然后，您可以使用XmlElement属性强制将xml元素写为平面列表（而不是嵌套）。

C＃Xml序列化列表<t>后代与Xml属性</t>

3 个答案: