Question

CREATE TRIGGER Supervisors
BEFORE INSERT OR UPDATE ON Employee
FOR EACH ROW
WHEN(new.EmpRank = 0 OR new.EmpRank = 1)
DECLARE
    supervisorRank INT;
BEGIN
    SELECT EmpRank INTO supervisorRank
    FROM Employee
    WHERE new.SupervisorID = Employee.Id;

    IF((new.SupervisorID IS NULL) OR (supervisorRank - new.EmpRank != 1)) THEN
        RAISE_APPLICATION_ERROR(-20004, 'Cannot insert/update record into table Employee. Invalid supervisor.');
    END IF;
END;

以上是每次运行查询时的触发器，导致我收到错误，指出触发器无效且重新验证失败

Answer 1

创建给定触发器时，它会报告编译错误：

Trigger SUPERVISORS compiled
Errors: check compiler log

编译错误来自一些缺少的冒号（＆＃34;：＆＃34;），它应该位于＆＃34; new＆＃34;的引用之前。和＃34;老＆＃34; 在触发器体内。

注意：＆＃34; WHEN＆＃34;中不需要冒号前缀。触发器的子句在这里：

WHEN(new.EmpRank = 0 OR new.EmpRank = 1)

此外，最好通过更细粒度的异常提前失败以便于调试，因此我已经添加了2个异常来处理NULL场景和NO_DATA_FOUND场景与＆＃34;排名不良＆＃ 34;异常。

以下是更新的代码，包括测试表定义和示例插入语句：

drop table employee
/

create table employee ( 
  id number,
  EmpRank number,
  SupervisorID number,
  primary key(id))
/

CREATE or replace TRIGGER Supervisors
BEFORE INSERT OR UPDATE ON Employee
FOR EACH ROW
WHEN(new.EmpRank = 0 OR new.EmpRank = 1)
DECLARE
    supervisorRank INT;
BEGIN
  if (:new.SupervisorID is null) then
    RAISE_APPLICATION_ERROR(-20006, 'Cannot insert/update record into table Employee. Required supervisor ID is missing.');
  end if;

  begin
    SELECT EmpRank INTO supervisorRank
    FROM Employee
    WHERE :new.SupervisorID = Employee.Id;
  exception when no_data_found then
    RAISE_APPLICATION_ERROR(-20005, 'Cannot insert/update record into table Employee. Supervisor ID not found.');
  end;

  IF (supervisorRank - :new.EmpRank != 1) THEN
    RAISE_APPLICATION_ERROR(-20004, 'Cannot insert/update record into table Employee. Employee rank is not valid for given supervisor.');
  END IF;
END;
/

insert into employee values ( 6, 1, null );
insert into employee values ( 5, 1, 6 );
insert into employee values ( 4, 2, null );
insert into employee values ( 3, 1, 4 );
insert into employee values ( 2, 0, 3 );
insert into employee values ( 1, 0, 3 );
insert into employee values ( 0, 0, 4 );

exit
/

以下是上述脚本的输出，显示各种异常消息。请注意，我使用新的SQLcl（sql.exe）而不是SQL * Plus，但结果应该相同。

SQLcl: Release 4.2.0.15.295.1605 RC on Tue Dec 08 17:07:23 2015

Copyright (c) 1982, 2015, Oracle.  All rights reserved.


Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options


Table EMPLOYEE dropped.


Table EMPLOYEE created.


Trigger SUPERVISORS compiled


Error starting at line : 36 in command -
insert into employee values ( 6, 1, null )
Error report -
SQL Error: ORA-20006: Cannot insert/update record into table Employee. Required supervisor ID is missing.
ORA-06512: at "APPS.SUPERVISORS", line 5
ORA-04088: error during execution of trigger 'APPS.SUPERVISORS'


Error starting at line : 37 in command -
insert into employee values ( 5, 1, 6 )
Error report -
SQL Error: ORA-20005: Cannot insert/update record into table Employee. Supervisor ID not found.
ORA-06512: at "APPS.SUPERVISORS", line 13
ORA-04088: error during execution of trigger 'APPS.SUPERVISORS'


1 row inserted.


1 row inserted.


1 row inserted.


1 row inserted.


Error starting at line : 42 in command -
insert into employee values ( 0, 0, 4 )
Error report -
SQL Error: ORA-20004: Cannot insert/update record into table Employee. Employee rank is not valid for given supervisor.
ORA-06512: at "APPS.SUPERVISORS", line 17
ORA-04088: error during execution of trigger 'APPS.SUPERVISORS'

Disconnected from Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options

“触发---无效且无法重新验证”

1 个答案: